import re
string = "Wacom Bamboo Connect Pen stylus id: 15 type: STYLUS"
lst = re.findall(r'^(.*\S)\s+id:\s*(\d+)\s+type:\s*(.+)', string)
# The first match (list element) is a tuple. Extract it:
lst = list(lst[0])
lst[1] = int(lst[1])
print(lst)
# ['Wacom Bamboo Connect Pen stylus', 15, 'STYLUS']
Use re.findall. The regex: r'^(.*\S)\s+id:\s*(\d+)\s+type:\s*(.+)' means: ^ : start of the string. .* :any character, repeated 0 or more times. \S : non-whitespace character. \s+ : whitespace character, repeated 1 or more times. \d+ : any digit, repeated 1 or more times. (PATTERN) : capture the patterns and return it. Here we capture 3 patterns.
import re
string = "Wacom Bamboo Connect Pen stylus id: 15 type: STYLUS"
lst = re.findall(r'^(.*\S)\s+id:\s*(\d+)\s+type:\s*(.+)', string)
# The first match (list element) is a tuple. Extract it:
lst = list(lst[0])
lst[1] = int(lst[1])
print(lst)
# ['Wacom Bamboo Connect Pen stylus', 15, 'STYLUS']
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评论（2）
使用
re.findall。正则：r'^（。*\ s）\ s+id：\ s*（\ d+）\ s+type：\ s*（。+）
^：String的开始。。*：重复0次或更多次的任何字符。\ s：非Whitespace字符。\ s+：whitespace字符，重复1次或更多次。\ d+：重复1次或更多次的数字。（模式）：捕获模式并将其返回。在这里，我们捕获3种模式。Use
re.findall. The regex:r'^(.*\S)\s+id:\s*(\d+)\s+type:\s*(.+)'means:^: start of the string..*:any character, repeated 0 or more times.\S: non-whitespace character.\s+: whitespace character, repeated 1 or more times.\d+: any digit, repeated 1 or more times.(PATTERN): capture the patterns and return it. Here we capture 3 patterns.要匹配第一个字符串在ID之前：
要匹配 id 您需要：
匹配类型您需要：
我建议您有查看 lookaheads and lookbehinds 。
To match the first string before id you need:
To match the id you need:
To match the type you need:
I would suggest you have a look at lookaheads and lookbehinds.