读取Groovy变量的YAML组件

发布于 2025-02-08 06:57:49 字数 551 浏览 0 评论 0原文

我有一个像下面的代码，

import groovy.yaml.YamlSlurper
def configYaml = '''\
---
application: "Sample App"
users:
- name: "mrhaki"
  likes:
  - Groovy
  - Clojure
  - Java
- name: "Hubert"
  likes:
  - Apples
  - Bananas
connections:
- "WS1"
- "WS2"
'''
// Parse the YAML.
def config = new YamlSlurper().parseText(configYaml)
def data1 = "users"
def date2 = "name"

println config.users.likes // printing correct 
println config.$data1.$data2 // getting error

需要从用户打印元素。NAME，并且需要从变量表单上打印它。例如“ printlnconfig。$ data1。$ data2”

原文

I have a code like below

import groovy.yaml.YamlSlurper
def configYaml = '''\
---
application: "Sample App"
users:
- name: "mrhaki"
  likes:
  - Groovy
  - Clojure
  - Java
- name: "Hubert"
  likes:
  - Apples
  - Bananas
connections:
- "WS1"
- "WS2"
'''
// Parse the YAML.
def config = new YamlSlurper().parseText(configYaml)
def data1 = "users"
def date2 = "name"

println config.users.likes // printing correct 
println config.$data1.$data2 // getting error

I need to print elements from users.name and I need to print it from variable form.
like "println config.$data1.$data2"

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π浅易 2025-02-15 06:57:49

您可以做下面的事情。

def config = new YamlSlurper().parseText(configYaml)
def data1 = "users"
def data2 = "name"

println config.users.likes
println config."$data1"."$data2"

You can do something like below.

def config = new YamlSlurper().parseText(configYaml)
def data1 = "users"
def data2 = "name"

println config.users.likes
println config."$data1"."$data2"

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