如何将QuerySelector与数据属性和类同时使用？
我的HTML看起来像这样，
<div class="slds-col slds-size_1-of-1 slds-hide" data-controllinganswer="a1ZC2000000O2n3MAC" data-questionid="a1fC20000000VgXIAU" data-id="a1fC20000000VmzIAE" data-selectedanswer="a1ZC2000000O2zxMAC">
但是当我尝试这样做时，
this.template.querySelector('[data-id="' + e.dataset.id + '"], .slds-show')
它仍然会返回一个元素，即使没有类slds-show。这是使用具有多个属性的QuerySelector的正确方法吗？
My html looks like this
<div class="slds-col slds-size_1-of-1 slds-hide" data-controllinganswer="a1ZC2000000O2n3MAC" data-questionid="a1fC20000000VgXIAU" data-id="a1fC20000000VmzIAE" data-selectedanswer="a1ZC2000000O2zxMAC">
But when I try to do this
this.template.querySelector('[data-id="' + e.dataset.id + '"], .slds-show')
It still returns me an element, even though there is no class as slds-show. Is this the right way of using queryselector with multiple attributes?
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Comma
selector1，selector2说具有Selector1或selector2的元素应匹配。如果您有一个space
selector1 selector2它将匹配的元素selector2在元素匹配selector1内，如果您有selector1selector2代码>没有空间，然后仅匹配一个匹配selector1和selector2的元素。因此，您的选择者应该是
The comma
selector1, selector2says that elements having selector1 or selector2 should match.If you have a space
selector1 selector2it will match an element matchingselector2inside an element matchingselector1, if you haveselector1selector2without space, then it matches only an element that matches bothselector1andselector2.So your selector should be