ASP .NET Core Razor页面 - 避免刷新页面
我有一种形式的拖曳按钮,第一个按钮以将网站信息添加到本地表格,第二个按钮以将社交媒体信息添加到另一个表格,此后所有信息在本地添加了所有信息, 然后,我可以单击“添加所有信息”按钮以同时将所有信息添加到数据库。
我的问题是,如何在不刷新页面的情况下将信息添加到表中?
addallinfo.cshtml:
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewWebSiteInfo.websiteName">Website URL</label>
<input type="text" asp-for="NewWebSiteInfo.websiteName" class="form-control" />
</div>
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewWebSiteInfo.websiteUrl">Website URL</label>
<input type="text" asp-for="NewWebSiteInfo.websiteUrl" class="form-control" />
</div>
<button type="submit" validatedisable="True" asp-page-handler="AddWebsiteInfo" class="btn btn-primary" >Add Website info</button>
<div class="mb-3">
@if (AddInfoModel.WebSitelist.Count > 0)
{
<div class="col-12 border p-3">
<table class="table table-striped table-bordered">
<thead style="background-color:lightgray">
<tr>
<th>WebsiteName</th>
<th>websiteURL</th>
</tr>
</thead>
<tbody>
@foreach (Website item in AddAllInfoModel.WebSitelist)
{
<tr>
<td>@item.WebsiteName</td>
<td>@item.websiteURL</td>
</tr>
}
</tbody>
</table>
</div>
}
</div>
</br>
</br>
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewSocialMediaInfo.SocialMediaName">Social Media</label>
<input type="text" asp-for="NewSocialMediaInfo.SocialMediaName" class="form-control" />
</div>
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewSocialMediaInfo.SocialMediaAccount">Account</label>
<input type="text" asp-for="NewSocialMediaInfo.SocialMediaAccount" class="form-control" />
</div>
<button type="submit" validatedisable="True" asp-page-handler="AddSocialMediaInfo" class="btn btn-primary" >Add socil Media info</button>
<div class="mb-3">
@if (AddInfoModel.SocialMedialist.Count > 0)
{
<div class="col-12 border p-3">
<table class="table table-striped table-bordered">
<thead style="background-color:lightgray">
<tr>
<th>SocialMediaName</th>
<th>SocialMediaAccount</th>
</tr>
</thead>
<tbody>
@foreach (SocialMedia item in AddAllInfoModel.SocialMedialist)
{
<tr>
<td>@item.SocialMediaName</td>
<td>@item.SocialMediaAccount</td>
</tr>
}
</tbody>
</table>
</div>
}
</div>
</br>
<div class="col-4 offset-2">
<button type="submit" class="btn btn-primary form-control"> Add all info </button>
</div>
</form> ```
AddAllInfo.cshtml.cs:
public void OnPostAddSocialMediaInfo()
{
SocialMedialist.Add(new SocialMedia { SocialMediaName = NewSocialMediaInfo.SocialMediaName,
SocialMediaAccount=NewSocialMediaInfo.SocialMediaAccount});
}
public void OnPostAddWebsiteInfo()
{
WebSitelist.Add(new WebSite { WebSiteName = NewWebSiteInfo.WebsiteName,
websiteUrl =NewWebSiteInfo.websiteUrl});
}
I have tow buttons in one Form, first button for add website info to a local table and second button for add social media info to another table, after all info added locally,
then I can click on 'add all info' button for add all info in same time to database.
My question is how can I add info to a table without refreshing the page?
AddAllInfo.cshtml:
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewWebSiteInfo.websiteName">Website URL</label>
<input type="text" asp-for="NewWebSiteInfo.websiteName" class="form-control" />
</div>
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewWebSiteInfo.websiteUrl">Website URL</label>
<input type="text" asp-for="NewWebSiteInfo.websiteUrl" class="form-control" />
</div>
<button type="submit" validatedisable="True" asp-page-handler="AddWebsiteInfo" class="btn btn-primary" >Add Website info</button>
<div class="mb-3">
@if (AddInfoModel.WebSitelist.Count > 0)
{
<div class="col-12 border p-3">
<table class="table table-striped table-bordered">
<thead style="background-color:lightgray">
<tr>
<th>WebsiteName</th>
<th>websiteURL</th>
</tr>
</thead>
<tbody>
@foreach (Website item in AddAllInfoModel.WebSitelist)
{
<tr>
<td>@item.WebsiteName</td>
<td>@item.websiteURL</td>
</tr>
}
</tbody>
</table>
</div>
}
</div>
</br>
</br>
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewSocialMediaInfo.SocialMediaName">Social Media</label>
<input type="text" asp-for="NewSocialMediaInfo.SocialMediaName" class="form-control" />
</div>
<div class="col-md-6 mb-3">
<label class="form-label" asp-for="NewSocialMediaInfo.SocialMediaAccount">Account</label>
<input type="text" asp-for="NewSocialMediaInfo.SocialMediaAccount" class="form-control" />
</div>
<button type="submit" validatedisable="True" asp-page-handler="AddSocialMediaInfo" class="btn btn-primary" >Add socil Media info</button>
<div class="mb-3">
@if (AddInfoModel.SocialMedialist.Count > 0)
{
<div class="col-12 border p-3">
<table class="table table-striped table-bordered">
<thead style="background-color:lightgray">
<tr>
<th>SocialMediaName</th>
<th>SocialMediaAccount</th>
</tr>
</thead>
<tbody>
@foreach (SocialMedia item in AddAllInfoModel.SocialMedialist)
{
<tr>
<td>@item.SocialMediaName</td>
<td>@item.SocialMediaAccount</td>
</tr>
}
</tbody>
</table>
</div>
}
</div>
</br>
<div class="col-4 offset-2">
<button type="submit" class="btn btn-primary form-control"> Add all info </button>
</div>
</form> ```
AddAllInfo.cshtml.cs:
public void OnPostAddSocialMediaInfo()
{
SocialMedialist.Add(new SocialMedia { SocialMediaName = NewSocialMediaInfo.SocialMediaName,
SocialMediaAccount=NewSocialMediaInfo.SocialMediaAccount});
}
public void OnPostAddWebsiteInfo()
{
WebSitelist.Add(new WebSite { WebSiteName = NewWebSiteInfo.WebsiteName,
websiteUrl =NewWebSiteInfo.websiteUrl});
}
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您可以使用JS将数据传递给处理程序,然后使用JS将HTML添加到TBODY,这是一个演示,可以将数据添加到表中,而无需刷新页面:
JS:
Handler:
You can use js to pass data to handler,and then use js to add html to tbody,here is a demo to add data to table without refresh the page:
js:
handler:
最好的方法是在JavaScript中运行POST请求,这不会刷新页面。
第二个选项是在邮政方法末尾再次调用GET方法,然后将模型传递给GET。因此,当页面刷新时,数据再次填写
The best way to do this is to run the post request in javascript, this will not refresh the page.
2nd option is by calling the get method again at the end of the post method and then passing the model with the data to the get. So that when the page refreshes the data is filled in again