从父班覆盖传递的函数
嘿，我的任务是创建ParentClass形状并将功能传递到不同的形状。由于电路计算采用不同的参数，因此我正在尝试覆盖该函数。它在警告后引发：“方法'circle.get_area（）'的签名'在形状中不匹配签名”。这根本可能吗？我该怎么做？以后是否可以工作？
class Shape(ABC):
@abstractmethod
def get_area(self, x_l, y_l):
pass
def move(self, newx, newy):
pass
class Circle(Shape):
def __init__(self, rad, x_pos, y_pos):
self.rad = rad
self.pos = (x_pos, y_pos)
self.area = self.get_area(self, self.rad)
def get_area(self, rad):
return(self.rad*self.rad*2*m.pi)
Hey my task is to create a parentclass Shape and pass the functions on to the different shapes. Since a Circlearea calculation takes different parameters I am trying to overwrite the function. It throws following warning: "Signature of method 'Circel.get_area()' does not match Signature in the base method in Shape". Is that possible at all? How would I have to do it? Should it work anyway later on?
class Shape(ABC):
@abstractmethod
def get_area(self, x_l, y_l):
pass
def move(self, newx, newy):
pass
class Circle(Shape):
def __init__(self, rad, x_pos, y_pos):
self.rad = rad
self.pos = (x_pos, y_pos)
self.area = self.get_area(self, self.rad)
def get_area(self, rad):
return(self.rad*self.rad*2*m.pi)
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