在通用类中使用通用接口

Question

如何使用在类中实现通用接口的类强制？ 这样的事情吗？

public interface IGeneric<T>
{
    T Value {get;}
}

//public class MyList<IGeneric<T>> {}//not allowed

Answer 1

这样的东西：

void Main()
{
    MyList<string> myList = new MyList<string>(new Generic());
}

public interface IGeneric<T>
{
    T Value { get; }
}

public class MyList<T>
{
    private IGeneric<T> _generic;
    public MyList(IGeneric<T> generic)
    {
        _generic = generic;
    }
}

public class Generic : IGeneric<string>
{
    public string Value => throw new NotImplementedException();
}

或这样：

void Main()
{
    MyList<Generic, string> myList = new MyList<Generic, string>();
    //Or MyList<IGeneric<string>, string> myList = new MyList<IGeneric<string>, string>();
}

public interface IGeneric<T>
{
    T Value { get; }
}

public class MyList<G, T> where G : IGeneric<T>
{
}

public class Generic : IGeneric<string>
{
    public string Value => throw new NotImplementedException();
}