如何将表达式的结果分配给bash中的变量
在以下bash脚本时，我试图将一个从JSON对象分配到变量的值。
#!/bin/bash
json_data='{"ip":"1.2.3.4", "country_code":"GB", "country_name":"United Kingdom"}'
echo json_data:
echo $json_data
echo country_code:
echo $json_data | jq '.country_code'
echo country_name:
echo $json_data | jq '.country_name'
cc=$json_data | jq '.country_code'
echo cc:
echo $cc
cn=$($json_data | jq '.country_name')
echo cn:
echo $cn
只是回应表达方式。 将表达式的值分配给变量CC或CN。
$ ./test.sh
json_data:
{"ip":"1.2.3.4", "country_code":"GB", "country_name":"United Kingdom"}
country_code:
"GB"
country_name:
"United Kingdom"
cc:
./test.sh: line 19: {"ip":"1.2.3.4",: command not found
cn:
$
我认为将表达式包装在$（...）中给出了我需要的功能，但这会导致错误。
谁能建议正确的语法？
In following bash script I'm trying to assign a value from a json object to a variable.
#!/bin/bash
json_data='{"ip":"1.2.3.4", "country_code":"GB", "country_name":"United Kingdom"}'
echo json_data:
echo $json_data
echo country_code:
echo $json_data | jq '.country_code'
echo country_name:
echo $json_data | jq '.country_name'
cc=$json_data | jq '.country_code'
echo cc:
echo $cc
cn=$($json_data | jq '.country_name')
echo cn:
echo $cn
Just echoing the expressions works.
Assigning the value of the expressions to variables cc or cn doesn't.
$ ./test.sh
json_data:
{"ip":"1.2.3.4", "country_code":"GB", "country_name":"United Kingdom"}
country_code:
"GB"
country_name:
"United Kingdom"
cc:
./test.sh: line 19: {"ip":"1.2.3.4",: command not found
cn:
$
I thought that wrapping an expression in $(...) gave the functionality I need, but that results in an error.
Could anyone advise as to the correct syntax?
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您未包装的功能。包装全部表达式，包括
echo。请记住引用变量扩展。使用ShellCheck检查您的脚本 - ShellCheck会通知您许多问题。
您可以将任何内容放入
$（...）中，也许这将清除它：You did not wrap enough. Wrap the whole expression, including
echo.Remember to quote variable expansions. Check your script with shellcheck - shellcheck will notify you of many problems.
You can put anything inside
$(...), maybe this will clear it: