一个人如何提取spacy中的动词短语？

Question

例如：

当人们认为所有可以买到的scoopers时，通常都会高估终极的冰淇淋scooper。

在这里我想摘下：

• 主题：“终极旋转冰淇淋scoopers”
• 副词子句：“当人们考虑所有可以购买的scoopers时，人们
• 通常都会被高估“

---

我具有以下功能 ”在

def get_subj(decomp):
    for token in decomp:
        if ("subj" in token.dep_):
            subtree = list(token.subtree)
            start = subtree[0].i
            end = subtree[-1].i + 1
            return str(decomp[start:end])

def get_obj(decomp):
    for token in decomp:
        if ("dobj" in token.dep_ or "pobr" in token.dep_):
            subtree = list(token.subtree)
            start = subtree[0].i
            end = subtree[-1].i + 1
            return str(decomp[start:end])

def get_advcl(decomp):
    for token in decomp:
        # print(f"pos: {token.pos_}; lemma: {token.lemma_}; dep: {token.dep_}")
        if ("advcl" in token.dep_):
            subtree = list(token.subtree)
            start = subtree[0].i
            end = subtree[-1].i + 1
            return str(decomp[start:end])

phrase = "Ultimate Swirly Ice Cream Scoopers are usually overrated when one considers all of the scoopers one could buy."

nlp = spacy.load("en_core_web_sm")
decomp = nlp(phrase)

subj = get_subj(decomp)
obj = get_obj(decomp)
advcl = get_advcl(decomp)

print("subj: ", subj)
print("obj: ", obj)
print("advcl: ", advcl)

​

subj:  Ultimate Swirly Ice Cream Scoopers
obj:  all of the scoopers
advcl:  when one considers all of the scoopers one could buy

---

​副总裁“通常被高估”的最终单词是“根”。

因此，随着root的子树返回整个句子，子树技术失败了。

Answer 1

您希望构造更像“动词群”的东西，其中您只使用root动词保留某些近亲依赖者，例如aux，cop 和advmod代码>，但不是nsubj，obj或adval> advcl。