找到成本，但它一直返回错误
my_money = input('How much money do you have? ')
boat_cost = 20 + 5
if my_money < boat_cost:
print('You can afford the boat hire')
else :
print('You cannot afford the board hire')
my_money = input('How much money do you have? ')
boat_cost = 20 + 5
if my_money < boat_cost:
print('You can afford the boat hire')
else :
print('You cannot afford the board hire')
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尝试此代码段，查看原始代码问题：
Try this code snippet and see the original code problem:
输入通常是字符串。为了使其工作，您需要使用y = int（x）将其转换为整合器。（尽管不是一个编程）中，
中也存在错误，它说如果他们的钱低于成本，他们可以负担得起租金。正确的代码，没有解决第二个错误，就会像这样：
inputis normally a string. In order for this to work you need to convert it to an integrer by usingy = int(x).There is also an error in the
if, albeit not a programming one, where it says that they can afford the hire if their money is less than the cost.The correct code, without fixing the second error, would look like this:
input（）函数允许在控制台中输入用户。但是该输入是一个字符串，您不能将其用作数学操作。
因此，
int（）是一个符合字符串并返回整数的函数。您必须使用
int（input（））要获得只能是数字的输入时。因此，替换：
如果说明逻辑是错误的，则应该是：
仅
当您的价格相同或更高时，您就可以负担得起船
The
input()function allows user input in the console.But that input is a string, you cannot use it as a mathametical operation.
So
int()is a function that takes a string and returns the integer.you have to use
int(input())when you want to get an input that can only be a number.so replace:
and your if statement logic is wrong it should be :
instead of
you can afford the boat only when your price is same or higher