使用切割创建从0开始的断裂

Question

如何使用cut（）函数来创建从0开始的断裂？

x <- seq(0, 102, length.out = 15)
cut(x, breaks = 10)

 [1] (-0.102,10.2] (-0.102,10.2] (10.2,20.4]   (20.4,30.6]   (20.4,30.6]   (30.6,40.8]   (40.8,51]     (40.8,51]     (51,61.2]     (61.2,71.4]   (71.4,81.6]   (71.4,81.6]  
[13] (81.6,91.8]   (91.8,102]    (91.8,102]   
Levels: (-0.102,10.2] (10.2,20.4] (20.4,30.6] (30.6,40.8] (40.8,51] (51,61.2] (61.2,71.4] (71.4,81.6] (81.6,91.8] (91.8,102]

Answer 1

基本函数 输出漂亮的数字。从文档中，我的重点。

计算一个大约n+1的序列​​均等间隔的“圆形”值，该值涵盖了x中值的范围。选择值以使它们是10 。

的1、2或5倍。

x <- seq(0, 102, length.out = 15)
cut(x, breaks = pretty(x, n = 10), include.lowest = TRUE)
#>  [1] [0,10]    [0,10]    (10,20]   (20,30]   (20,30]   (30,40]   (40,50]  
#>  [8] (50,60]   (50,60]   (60,70]   (70,80]   (80,90]   (80,90]   (90,100] 
#> [15] (100,110]
#> 11 Levels: [0,10] (10,20] (20,30] (30,40] (40,50] (50,60] (60,70] ... (100,110]

^由