类型错误：比较循环的整数和列表

发布于 2025-02-06 22:43:38 字数 421 浏览 2 评论 0原文

python在这里。如何解决比较字典循环中的列表和int错误，请提供帮助！

from random import *
passenger = list(range(1,51))

timelist = []
for i in range(1,51):
    n = randint(15,51)
    timelist.append(n)
    
passenger_time = {'passenger':passenger, 'timelist':timelist}

for x in passenger_time.values():
    if 40 > x > 15:
        print('passenger {} accepted'.format(y))
    else:
        print('not accepted')

原文

Python beginner here.
How can you solve comparing list and int error in for loop of a dictionary, please help!

from random import *
passenger = list(range(1,51))

timelist = []
for i in range(1,51):
    n = randint(15,51)
    timelist.append(n)
    
passenger_time = {'passenger':passenger, 'timelist':timelist}

for x in passenger_time.values():
    if 40 > x > 15:
        print('passenger {} accepted'.format(y))
    else:
        print('not accepted')

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洋洋洒洒 2025-02-13 22:43:38

我怀疑您想要的是：

for pass, time in zip(passenger_times['passenger'], passenger_times['timelist']):
    if 15 < time < 40:
        print(f'passenger {pass} is accepted')

这在两个列表中并行迭代。它检查一个列表中的值，然后从另一个列表中打印相应的值。

您的代码只是在字典中的两个值迭代。第一次，x包含整个pastenger列表，第二次包含整个timelis list。做15＆lt是没有意义的； x＆lt; 40当x是列表时。

I suspect what you want is:

for pass, time in zip(passenger_times['passenger'], passenger_times['timelist']):
    if 15 < time < 40:
        print(f'passenger {pass} is accepted')

This iterates over the two lists in parallel. It checks the value in one of the lists, then prints the corresponding value from the other list.

Your code is just iterating over the two values in the dictionary. The first time, x contains the entire passenger list, the second time it contains the entire timelis list. It makes no sense to do 15 < x < 40 when x is a list.

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