如何从VUEX中获取模块状态道具作为单个计算的道具（不是作为对象的道具）？

Question

我有一个带有单个模块的状态：

   const charactersModule = {
      state: () => ({
        characters: [],
        isLoading: false,
        totalPages: 0,
        currentPage: 1,
        itemsPerPage: ITEMS_PER_PAGE,
      }),
      getters: {},
      mutations: {},
      actions: {
        async getCharacters({state}, page = state.currentPage) {
          try {
            state.isLoading = true;
            const res = await fetch(`${BASE_URL}character/?page=${page}`);
    
            if (res.ok) {
              const { info, results } = await res.json();
    
              state.characters = results;
            }
          } catch (e) {
            console.log(e);
          } finally {
            state.isLoading = false;
          }
        },
      },
    };
    
    export default createStore({
      modules: {
        characters: charactersModule,
      },
    });

然后在sfc中：

// some component

    ...
      methods: {
        ...mapActions(['getCharacters']),
        }
    
      computed: {
        ...mapState(['characters'])
      },
    
      mounted() {
        this.getCharacters()
      },

我希望在此SFC内部我可以访问计算的属性：字符，isloading，totalpapges，currentpage和ittemperpage 。我实际上从... MapState（['''']）是一个具有所有这些道具的对象，但是我需要将它们作为单个计算的道具（不是作为对象的一部分）。我该怎么做？

Answer 1

尝试使用createNamespacedHelpers通过模块名称的前缀来帮助您的状态：

import { createNamespacedHelpers } from 'vuex'

const { mapState, mapActions } = createNamespacedHelpers('characters')

 ...
      methods: {
        ...mapActions(['getCharacters']),
        }
    
      computed: {
        ...mapState(['characters'])
      },
    
      mounted() {
        this.getCharacters()
      },