在一个SQL查询中同一列中同一类型的不同值的总和值

发布于 2025-02-06 14:23:42 字数 599 浏览 3 评论 0 原文

目前,我正在执行以下操作以计算一列中不同语言的付款方式:

$sql = "SELECT `payment`, count(*) as number FROM Test GROUP BY `payment` ";

结果:

Cash 2
Bar 4
Credit-Card 5
Kreditkarte 8
Invoice 12
Rechnung 27

任何想法如何以一个SQL查询中的不同语言总和相同的付款方式来获取以下内容,以获取以下内容显然在括号中的一部分:

Bar 6 (sum of Cash and Bar)
Kreditkarte 13 (sum of Credit-Card and Kreditkarte)
Rechnung 39 (sum of Invoice and Rechnung)

表名称:测试

payment       
===========
Cash
Bar
Credit-Card
Kreditkarte
Invoice
Rechnung

At the moment im doing the following to count the payment methods in different languages in a column:

$sql = "SELECT `payment`, count(*) as number FROM Test GROUP BY `payment` ";

Result:

Cash 2
Bar 4
Credit-Card 5
Kreditkarte 8
Invoice 12
Rechnung 27

Any idea how to sum the same payment methods in different languages in one SQL query to get the following without the part in the brackets obviously:

Bar 6 (sum of Cash and Bar)
Kreditkarte 13 (sum of Credit-Card and Kreditkarte)
Rechnung 39 (sum of Invoice and Rechnung)

Table Name: Test

payment       
===========
Cash
Bar
Credit-Card
Kreditkarte
Invoice
Rechnung

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惯饮孤独 2025-02-13 14:23:42

使用案例更改'现金' 'bar''信用卡' to >'Kreditkarte'和'发票' 'rechnung' and complut and complut unt it its:

SELECT CASE payment
         WHEN 'Cash' THEN 'Bar'
         WHEN 'Credit-Card' THEN 'Kreditkarte'
         WHEN 'Invoice' THEN 'Rechnung'
         ELSE payment
       END AS payment, 
       COUNT(*) AS number 
FROM Test 
GROUP BY 1;

Use a CASE expression that changes 'Cash' to 'Bar', 'Credit-Card' to 'Kreditkarte' and 'Invoice' to 'Rechnung' and group by its result:

SELECT CASE payment
         WHEN 'Cash' THEN 'Bar'
         WHEN 'Credit-Card' THEN 'Kreditkarte'
         WHEN 'Invoice' THEN 'Rechnung'
         ELSE payment
       END AS payment, 
       COUNT(*) AS number 
FROM Test 
GROUP BY 1;
~没有更多了~
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