SQL：计算总和达到特定值的行数

发布于 2025-02-06 12:01:55 字数 1871 浏览 5 评论 0原文

我有一个看起来或多或少类似于此表的数据。让我们称此“费用”表。

日期	运输	水果	蔬菜
2022-05-25	10	10	30
2022-05-26	10	0	40
2022-05-27	10	20	20 40
2022-05-28	10	20 30	20 30
2022-05-29	10	0	60
2022-05-05-30	10	10	30
2022-05-31	10	10	40
2022-06-01	10	10	30
2022-06-06-02	10	20 30	30
2022-06-06-03	10	30 30	40
2022-06-06-04	10	10 0	20
2022-06-06-06-05	30	30 30 30	30 30 30
2022-06-06	10	20	30
2022-06-07	10	0	30
2022-06-06-08	10	0	30
2022-06-09	10	10	20
2022-06-10	10	30 30	30

我想知道有多少天，用于多少天五月和六月的几个月，水果的总和和蔬菜等于或大于50。

我希望得到的答案是4天5月（05-27,05-28，05-29，05-31）和6月的5天（06-02，06-02，06-03，06-05，06-05，06-06 ，06-10）

我尝试使用此脚本，但是...

select date_format（date，'％m''％y'）， count （date）< br> 来自费用
组由 date_format（日期，'％m''％y'）
具有 sum（水果 +蔬菜）＆gt; = 50

...而不是仅计算每月的数字，其水果总和等于或大于50，在两个月的时间里，它在桌上均计算，也就是说，它的答案是5月的7天和6月的10天。

我正在使用MySQL的最新版本。

原文

I have a data that looks like more or less like this table. Let's call this "expenses" table.

date	transportation	fruits	vegetables
2022-05-25	10	10	30
2022-05-26	10	0	40
2022-05-27	10	20	40
2022-05-28	10	20	30
2022-05-29	10	0	60
2022-05-30	10	10	30
2022-05-31	10	10	40
2022-06-01	10	10	30
2022-06-02	10	20	30
2022-06-03	10	30	40
2022-06-04	10	0	20
2022-06-05	10	30	30
2022-06-06	10	20	30
2022-06-07	10	0	30
2022-06-08	10	0	30
2022-06-09	10	10	20
2022-06-10	10	30	30

I want to know how many days, for the months of May and June, the sum of fruits and vegetables was equal to or greater than 50.

The answer that I'm expecting to get is 4 days for May (05-27,05-28, 05-29, 05-31) and 5 days for June (06-02, 06-03, 06-05, 06-06, 06-10)

I tried to use this script, however...

SELECT date_format(date, '%M' '%Y'), COUNT(date)
FROM expenses
GROUP BY date_format(date, '%M' '%Y')
HAVING SUM(fruits + vegetables)>=50

...instead of counting only the number days per month whose sum of fruits and vegetables was equal to or greater than 50, it counts all days in the table for the two months, that is to say, it yields an answer of 7 days for May and 10 days for June.

I am using the latest version of MySQL.

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初见 2025-02-13 12:01:55

而不是具有子句，而是用过滤行。

查询

select date_format(date, '%M' '%Y') as month, count(*) as no_of_days
from expenses
where fruits + vegetables >= 50
group by date_format(date, '%M' '%Y');

sql小提琴

Instead of having clause, filter the rows with Where.

Query

select date_format(date, '%M' '%Y') as month, count(*) as no_of_days
from expenses
where fruits + vegetables >= 50
group by date_format(date, '%M' '%Y');

SQL Fiddle

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