尝试使用Elixir中的公共密钥编码base64编码密码

Question

我尝试了很多不同的方式，但是这种方式使我走了最远。我在PEM文件中有公钥。我通过使用以下：public_key的一些代码在密钥文件中读取，但是尝试对其进行编码只是返回错误。

                base64_password = Base.encode64(enc_password)
                rsa_public_key_path = "/Users/owen/loomis/io_backend/priv/certs/in2publickey.key"
                {:ok, pub_key_string} = File.read(rsa_public_key_path)
                IO.puts("got the file " <> pub_key_string)
                public_key1 = "/Users/owen/loomis/io_backend/priv/certs/in2publickey.pem" |> File.read!() |> :public_key.pem_decode()
                IO.puts("got the key")
                public_key2 = Enum.at(public_key1, 0)
                IO.puts("got key2")
                {:RSAPublicKey, public_key3} = public_key2
                {:ok, cipher_text} = ExPublicKey.encrypt_public(base64_password, public_key3)

输出是：

got the file -----BEGIN RSA PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQDBgAoZDSn2tQiWlmAajIGmptuz
Olk7nYiIpz6IC14hdE27S+lpxG9UvNmsuogHAUagNnlnWUlNNyqBbx2ntSlihKpb
cu9SseTD5GYFCUn0KxMFqxodEWPNDg5lq5G+Pd1llvXYrMBaN8w3qssI7QvbOqOt
RjuLvzwCsNG2oCgzAwIDAQAB
-----END RSA PUBLIC KEY-----

got the key
got key2

异常返回是：

   ** (MatchError) no match of right hand side value: {:RSAPublicKey, <<48, 129, 159, 48, 13, 6, 9, 42, 134, 72, 134, 247, 13, 1, 1, 1, 5, 0, 3, 129, 141, 0, 48, 129, 137, 2, 129, 129, 0, 193, 128, 10, 25, 13, 41, 246, 181, 8, 150, 150, 96, 26, 140, 129, 166, 166, 219, 179, ...>>, :not_encrypted}
        (io_backend 0.1.0) lib/io_backend_web/controllers/AuthenticationController.ex:102: IoBackendWeb.AuthenticationController.show/2
        (io_backend 0.1.0) lib/io_backend_web/controllers/AuthenticationController.ex:1: IoBackendWeb.AuthenticationController.action/2
        (io_backend 0.1.0) lib/io_backend_web/controllers/AuthenticationController.ex:1: IoBackendWeb.AuthenticationController.phoenix_controller_pipeline/2
        (phoenix 1.6.6) lib/phoenix/router.ex:355: Phoenix.Router.__call__/2
        (io_backend 0.1.0) lib/io_backend_web/endpoint.ex:1: IoBackendWeb.Endpoint.plug_builder_call/2
        (io_backend 0.1.0) lib/plug/debugger.ex:136: IoBackendWeb.Endpoint."call (overridable 3)"/2
        (io_backend 0.1.0) lib/io_backend_web/endpoint.ex:1: IoBackendWeb.Endpoint.call/2
        (phoenix 1.6.6) lib/phoenix/endpoint/cowboy2_handler.ex:54: Phoenix.Endpoint.Cowboy2Handler.init/4
        (cowboy 2.9.0) /Users/owen/loomis/io_backend/deps/cowboy/src/cowboy_handler.erl:37: :cowboy_handler.execute/2
        (cowboy 2.9.0) /Users/owen/loomis/io_backend/deps/cowboy/src/cowboy_stream_h.erl:306: :cowboy_stream_h.execute/3
        (cowboy 2.9.0) /Users/owen/loomis/io_backend/deps/cowboy/src/cowboy_stream_h.erl:295: :cowboy_stream_h.request_process/3
        (stdlib 3.17) proc_lib.erl:226: :proc_lib.init_p_do_apply/3

我能够到达“ get key2”点，但是它抱怨下一行，我试图剥离仅密钥而不是：rsapublickey atom 。 （我已经尝试使用public_key2进行编码，并给出了匹配错误。我什至不确定Expublickey是否会rsa。实际读取字符串的调用是对Erlang函数的调用。我需要一个相应的Erlang代码来制作加密有更好的方法？