如何从raku中的IO :: socket :: async获得一行？

发布于 2025-02-06 04:08:43 字数 229 浏览 0 评论 0原文

因此，我有：

    my $conn = await IO::Socket::Async.connect('127.0.0.1', 12340);  
    $conn.print: "GET /rest HTTP/1.1\r\n\r\n";

如何仅接收服务器的第一行？

我可以在时使用并在其中使用一些逻辑，但是有一种简单的方法，对吗？

原文

So, I have this:

    my $conn = await IO::Socket::Async.connect('127.0.0.1', 12340);  
    $conn.print: "GET /rest HTTP/1.1\r\n\r\n";

How to receive just the first line from the server ?

I could use whenever and put some logic in it, but there's a simpler way, right ?

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音栖息无 2025-02-13 04:08:44

如果您真的只想要第一行，并且不在乎其余的响应，那么您可以做到这一点：

my $first-line = await $conn.Supply.lines.first;

也就是说，获取代表响应流的supply，是否将其拆分为行（这导致了行的供应），并采用到达的第一行。一行以外收到的任何数据都将被丢弃。

io :: socket :: async在提供数据数据包时起作用。它没有提供面向线路的接口；如果协议确实如此简单，就像逐条阅读，那么每当$ conn.supply.lines -lines-＆gt; $ line {} 将执行此操作（并且处理行为正确分配的行）。

If you really only want the first line, and don't care about the rest of the response, then you can do this:

my $first-line = await $conn.Supply.lines.first;

That is, get the Supply representing the response stream, have it split into lines (which results in a Supply of lines), and take the first line that arrives. Any data received beyond the first line will be discarded.

IO::Socket::Async works in terms of providing packets of data as they arrive. It doesn't get into providing a line-oriented interface; if a protocol really is so simple as reading line by line, then a react whenever $conn.Supply.lines -> $line { } will do it (and handles lines split over packets correctly).

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