在密码中检查至少4个不同的字符

发布于 2025-02-06 03:27:55 字数 182 浏览 6 评论 0原文

我需要将字符串（密码）是否包含：字母，数字，至少6个字符（长度）和（此解决问题）至少4个不同的字符。

（密码只能包含字母或数字，但至少

4个不同的字符。）到目前为止

/^\S(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{6,}$/i

有

原文

I need regex that check if a String (password) contains: letters, numbers, at least 6 character (length) AND (this going the problem) at least 4 different characters.

(Password can contains only letters or only numbers but at least 4 different char.)

So far i have been using this but this can not check at least 4 different characters

/^\S(?=.*[A-Za-z])(?=.*\d)[A-Za-z\d]{6,}$/i

Thx if u have any Idea

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删除→记忆 2025-02-13 03:27:55

假设字符串可以包含字母和数字，这是满足您要求的JavaScript Regex的一个示例：

const regex = /^(?=.*(.).*(?!\1)(.).*(?!\1|\2)(.).*(?!\1|\2|\3).)[a-z\d]{6,}$/i;

console.log(regex.test('abc'));       // false
console.log(regex.test('abcbaa'));    // false

console.log(regex.test('abcdaa'));    // true

Assuming the string can contain only letters and numbers, an example of a JavaScript regex that fulfills your requirements is:

const regex = /^(?=.*(.).*(?!\1)(.).*(?!\1|\2)(.).*(?!\1|\2|\3).)[a-z\d]{6,}$/i;

console.log(regex.test('abc'));       // false
console.log(regex.test('abcbaa'));    // false

console.log(regex.test('abcdaa'));    // true

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几味少女 2025-02-13 03:27:55

如果您不介意额外的检查以使至少4个不同的角色部分更加灵活，则可以将图案与集合结合使用。

const regex = /^(?=[^a-z\n]*[a-z])(?=[^\d\n]*\d)[a-z\d]{6,}$/i;
const check = (s) => regex.test(s) && (new Set(s)).size > 3;
[
  "abc5",
  "abcdef",
  "123456",
  "aaaaa1",
  "aaaa12",
  "abcbaa",
  "abcdaa",
  "aaa123",
  "abc1aa",
  "1112ab"

].forEach(s =>
  console.log(`${s} --> ${check(s) ? "Match" : "No match"}`)
)

If you don't mind an extra check to make the at least 4 different characters part a bit more flexible, you can use your pattern in combination with a Set.

const regex = /^(?=[^a-z\n]*[a-z])(?=[^\d\n]*\d)[a-z\d]{6,}$/i;
const check = (s) => regex.test(s) && (new Set(s)).size > 3;
[
  "abc5",
  "abcdef",
  "123456",
  "aaaaa1",
  "aaaa12",
  "abcbaa",
  "abcdaa",
  "aaa123",
  "abc1aa",
  "1112ab"

].forEach(s =>
  console.log(`${s} --> ${check(s) ? "Match" : "No match"}`)
)

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