拍照后，如何去下一个屏幕？斯威夫特

Question

我在导航方面有问题。 我需要拍照，然后打开带有按钮和拍摄图像的新屏幕。现在，它打开相同的屏幕，但使用拍摄图像。

这是第一个屏幕

这是同一屏幕，但是我需要在这里使用另一个按钮的另一个视图

带有按钮的照片

” alt = “

import Foundation
import SwiftUI

class ImagePickerCoordinator: NSObject, UINavigationControllerDelegate, UIImagePickerControllerDelegate {

    @Binding var isShown: Bool
    @Binding var image: Image?

    init(isShown: Binding<Bool>, image: Binding<Image?>) {
        _isShown = isShown
        _image = image
    }

    func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {
        let uiImage = info[UIImagePickerController.InfoKey.originalImage] as! UIImage
        image = Image(uiImage: uiImage)
        isShown = false
    }

    func imagePickerControllerDidCancel(_ picker: UIImagePickerController) {
        isShown = false
    }
}

struct ImagePicker: UIViewControllerRepresentable {

    @Binding var isShown: Bool
    @Binding var image: Image?

    func updateUIViewController(_ uiViewController: UIImagePickerController, context: UIViewControllerRepresentableContext<ImagePicker>) {

    }

    func makeCoordinator() -> ImagePickerCoordinator {
        return ImagePickerCoordinator(isShown: $isShown, image: $image)
    }

    func makeUIViewController(context: UIViewControllerRepresentableContext<ImagePicker>) -> UIImagePickerController {
        let picker = UIImagePickerController()
        picker.delegate = context.coordinator
        if !UIImagePickerController.isSourceTypeAvailable(.camera){
            picker.sourceType = .photoLibrary
        } else {
            picker.sourceType = .camera
        }
        return picker
    }
}

import SwiftUI

struct ContentView: View {

    @State private var showImagePicker: Bool = false
    @State private var image: Image? = nil

    var body: some View {
        VStack {

            image?.resizable()
                .scaledToFit()

            Button("Attach the image") {
                self.showImagePicker = true
            }.padding()
                .background(Color.blue)
                .foregroundColor(Color.white)
                .cornerRadius(10)
        }.sheet(isPresented: self.$showImagePicker) {
            PhotoCaptureView(showImagePicker: self.$showImagePicker, image: self.$image)
        }
    }
} 

”强>

import SwiftUI

struct PhotoCaptureView: View {

    @Binding var showImagePicker: Bool
    @Binding var image: Image?


    var body: some View {
        ImagePicker(isShown: $showImagePicker, image: $image)
    }
}

#if DEBUG
struct PhotoCaptureView_Previews: PreviewProvider {
    static var previews: some View {
        PhotoCaptureView(showImagePicker: .constant(false), image: .constant(Image("")))
    }
}
#endif

Answer 1

这很简单，您可以使用NotificationCenter。
在didfinishpickingmediawithinfo函数中，您可以发布通知，在ContentView中使用通知发布者更改状态值。
因此，在contentview中：

.onReceive(NotificationCenter.default.publisher(for: Notification.Name("NotificationName"))) { _ in
  move.toggle()
    }
    .sheet(isPresented: $move) {
        AnotherContentView()
        
    }

以及在didfinishpickingmediawithinfo函数中：

NotificationCenter.default.post(name: Notification.Name("NotificationName"), object: nil, userInfo: nil)