pygame sprite赢得了移动，当按键按下时退出游戏

Question

因此，当按下钥匙时，我无法让我的精灵跳跃。我已经解决了一些错误，但是现在我有一个说明：文件“/users/josh/desktop/fresh/main.py”，第52行，in screen.blit（player，player_rect） TypeError：闪电的无效目的地位置

import pygame
from sys import exit
pygame.init()

screen = pygame.display.set_mode((800,400))
pygame.display.set_caption('Shooter Mania')
text = pygame.font.Font(None, 50)
clock = pygame.time.Clock()

# 
bg = pygame.image.load('background.png')
# 
player = pygame.image.load('player.png').convert_alpha()
player_rect = player.get_rect(midbottom=(80,300))
playerX = 0
playerY = 0
# 
score_surf = text.render('SCORE:', False, 'white')
score_rect = score_surf.get_rect(center=(400,50))
# 
enemy = pygame.image.load('enemy.png').convert_alpha()
enemy_rect = enemy.get_rect(bottomright=(600,300))
# 
# 
# 

while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            exit()
        elif event.type == pygame.KEYDOWN:
            if event.key == pygame.K_SPACE:
                player_rect = player_rect.move_ip(0,5)
                print(f'Jump')
    
    screen.blit(bg, (0,0))
    pygame.draw.rect(screen, 'Pink',score_rect)
    screen.blit(score_surf,score_rect)

    enemy_rect.x -= 4

    if enemy_rect.right <= 0:
        enemy_rect.left = 800
    screen.blit(enemy,enemy_rect)

    # if player_rect.y <= 400:
    #     player_rect.y = 300
    # playerX +=1
    # player_rect.y += playerX
    
    screen.blit(player, player_rect)


    pygame.display.update()
    clock.tick(60)

Answer 1

移动矩形时，您会使用 更新到适当的rect（因此名称）并没有返回，即none。然后将其分配到player_Rect变量，然后传递到screen.blit（），失败。解决方案不是使用移动的原位版本：

            if event.key == pygame.K_SPACE:
                player_rect = player_rect.move(0, 5)
                print(f'Jump')

这将返回更新的rect并将其分配给player_Rect。另外，您可以不用分配使用现场版本：

            if event.key == pygame.K_SPACE:
                player_rect.move_ip(0, 5)
                print(f'Jump')