如何提取变量名（作为变量列表中的元素）并将其转换为字符串？

Question

nameof（）可以用来将变量的名称打印为字符串，而不是其值本身：

from varname import nameof
var = 'Hello!'
print (nameof(var))

#Output:
var

我需要它的原因是因为我想打印列表的每个元素的值当它正在通过时：

from varname import nameof

green = 3
blue = 6
black = 9
white = 1
purple = 8

list_colors = [green, blue, black, white, purple]

for color in list_colors:
    print("The color being looked at is:", nameof(color))

我得到的输出是：

The color being looked at is: color
The color being looked at is: color
The color being looked at is: color
The color being looked at is: color
The color being looked at is: color

但是，我需要以下作为输出（也不是存储在每个变量中的数字值）：

The color being looked at is: green
The color being looked at is: blue
The color being looked at is: black
The color being looked at is: white
The color being looked at is: purple

任何人都可以帮助我吗？

Answer 1

如果您想这样做，我从：

在列表中获取变量名称 < /p>

for i in range(len(list_colors)):
print([k for k,v in globals().items() if id(v) == id(list_colors[i])][0])

我不知道它的工作原理，我会使用一个2D阵列（绝对不是最好的解决方案），但是您可以去。

Answer 2

使用retireve_name by juan isaza 来自获取变量的名称作为字符串<< /a>

import inspect

def retrieve_name(var):
    """
    Gets the name of var. Does it from the out most frame inner-wards.
    :param var: variable to get name from.
    :return: string
    """
    for fi in reversed(inspect.stack()):
        names = [var_name for var_name, var_val in fi.frame.f_locals.items() if var_val is var]
        if len(names) > 0:
            return names[0]

green = 3
blue = 6
black = 9
white = 1
purple = 8

list_colors = [green, blue, black, white, purple]

for color in list_colors:
    print("The color being looked at is:", retrieve_name(color))

输出：

The color being looked at is: green
The color being looked at is: blue
The color being looked at is: black
The color being looked at is: white
The color being looked at is: purple