如何从此字符串中删除前5个字符？

发布于 2025-02-05 11:33:08 字数 714 浏览 1 评论 0原文

我有一个类似的字符串（HTML选择列表）：

const config = {
    "celsius": {
        "celsius": v => v,
        "fahrenheit": v => v * 1.8 + 32,
        "kelvin": v => v + 273.15,
        "rankine": v => (v + 273.15) * 1.8,
        "reaumur": v => v * 0.8,
    },
    // more...
}

我想

var listOperation = config[listFromV][listToV].substring(5);
document.getElementById("operationPlace").innerHTML = listOperation;
// now it looks like this: v => v or v => v * 1.8 + 32 etc.
// should look like this: v or v * 1.8 + 32 etc. (I'd like to change that "v" to numbers from the input (inputPlace) too)

从尝试使用substring的输出（操作场所）中剪切前5个字符，但它不起作用。有办法这样做吗？

原文

I have a string like this (HTML select list):

const config = {
    "celsius": {
        "celsius": v => v,
        "fahrenheit": v => v * 1.8 + 32,
        "kelvin": v => v + 273.15,
        "rankine": v => (v + 273.15) * 1.8,
        "reaumur": v => v * 0.8,
    },
    // more...
}

And I want to cut the first 5 characters from the output (operationPlace)

var listOperation = config[listFromV][listToV].substring(5);
document.getElementById("operationPlace").innerHTML = listOperation;
// now it looks like this: v => v or v => v * 1.8 + 32 etc.
// should look like this: v or v * 1.8 + 32 etc. (I'd like to change that "v" to numbers from the input (inputPlace) too)

I tried using substring, but it didn't work. Is there a way to do this?

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抚笙 2025-02-12 11:33:08

您可以通过在其上调用.toString来获取字符串形式的函数的定义，然后调用.substring以摆脱功能签名部分：

var listOperation = config[listFromV][listToV];
document.getElementById("operationPlace").innerHTML = listOperation.toString().substring(5);

请注意这是幼稚的方法，只能适用于签名的签名，由单个1个字符的长论点和箭头符号组成，而没有括号。

You can obtain the definition of a function in the form of a string by calling .toString on it, then call .substring to get rid of the function signature part:

var listOperation = config[listFromV][listToV];
document.getElementById("operationPlace").innerHTML = listOperation.toString().substring(5);

Note that this is approach is naive and will only work for functions whose signature is composed of a single 1-character long argument and arrow notation without parenthesis.

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