如何将字符串字符的ASCII值解释为C中的字符？

Question

我有一系列代表字母字符[a，z]，[a，z]和“” ASCII值的数字序列。我可以在char中获得一个值之一的ASCII值（即char = 76），但是当我尝试进行界限检查并将其附加到结果时，我似乎无法获得“ L”而不是76和76和不能将CHAR值与边界的ASCII值进行比较（即A = 65）。我该如何在C中这样做？

//input would be something like char* source = "76111114..."
// result should be "Lor"
for(int i = 0; i < strLen; i+=2)
{
    char actualChar = ' ';
    
    //get two numbers as a character
    strncpy(&actualChar, source + i, 2);
    
    //this prints out 76
    printf("%s\n", &actualChar);

    //this prints out 55
    printf("%d\n", actualChar);
    
    
    //check if the character is a space
    if(actualChar == 32)
    {
        //append
         strncat(result, &actualChar, 2);
         printf("Added space : %s\n", result);
         continue;
    }
    
    //[A, Z]
    else if(actualChar >= 65 && actualChar <= 90)
    {
        //append
        strncat(result, &actualChar, 2);
        printf("Added 2 digit char: %s, %s\n", &actualChar ,result);
        continue;
    }
    
    else
    {
        //add one number to the char and check again
        strncpy(&actualChar, source + i, 3);
        
        //[a, z]
        if(actualChar >= 97 && actualChar <= 122)
        {
            ++i;
            
            //append
            strncat(result, &actualChar, 3);
            printf("Added 3 digit char: %s, %s\n", &actualChar ,result);
            
            continue;
        }
        
        //not a valid char
        else
        {
            printf("Not valid char: %s", &actualChar);
            return 0;
        }
    }
}

我希望结果是“ lor”，但我得到的是“ 7611114”。

Answer 1

如评论中提到的，sscanf（源，“％2D”，＆amp; muthChar）和sscanf（来源，“％3D”，＆amp; natualChar）是获得它的最简单方法，尽管我必须将其施放为int*才能使SSCANF工作：

sscanf（source+ i，“％2D”，（int*），（＆amp; amp; muthatch））;>