是否有任何方法可以将2个循环绑定在C＃中的循环中。

发布于 2025-02-05 06:15:14 字数 529 浏览 0 评论 0原文

它从MCU读取消息并将它们存储在8个字节[0]〜[7]的代码中，
特别是在上半年存储前4个元素，索引[0]〜[3]和接下来的四个元素在接下来的半部分中，索引[4]〜[7]
是否有任何更轻松的方法？

halfbytelength = 4;
bytelength =8;

case 0:

 for (index = 0; index <halfbytelength; index += 1)
 {
    Array1[index] = msg[index];
 }
 for (index = halfbytelength; index < bytelength; index += 1)
 {
   Array2[index - halfbytelength] = msg[index];
 }
 MainArray[0] = ASCIIEncoding.ASCII.GetString(Array1);
 MainArray[1] = ASCIIEncoding.ASCII.GetString(Array2);

原文

The code where it reads Messages from MCU and stores them in an array of 8 bytes[0]~[7],
specifically storing the first 4 elements in the first half, indexes [0] ~[3], and the next four elements in the next half, indexes [4] ~[7]
Is there any easier way to do it?

halfbytelength = 4;
bytelength =8;

case 0:

 for (index = 0; index <halfbytelength; index += 1)
 {
    Array1[index] = msg[index];
 }
 for (index = halfbytelength; index < bytelength; index += 1)
 {
   Array2[index - halfbytelength] = msg[index];
 }
 MainArray[0] = ASCIIEncoding.ASCII.GetString(Array1);
 MainArray[1] = ASCIIEncoding.ASCII.GetString(Array2);

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GRAY°灰色天空 2025-02-12 06:15:14

不需要编写循环以自己复制字节。例如，您可以使用跨度切片阵列。

var array1 = msg.AsSpan().Slice(0, 4).ToArray();
var array2 = msg.AsSpan().Slice(4, 4).ToArray();

我想说的是，阅读要容易得多。或<添加扩展方法将跨度转换为直接将跨度转换为字符串。

或者您可以使用阵列。副本

Array.Copy(msg, 0, array1, 0, 4);
Array.Copy(msg, 4, array2, 0, 4);

，但我发现阅读不太容易。

关于性能，我不会期望有很大的差异。我希望将数组转换为字符串比复制几个字节要多。但是，如果避免分配的任何方法在紧密的循环中运行，则可能会具有一定的优势。

There should be no need to write the loop to copy bytes yourself. You could for example use spans to slice the array.

var array1 = msg.AsSpan().Slice(0, 4).ToArray();
var array2 = msg.AsSpan().Slice(4, 4).ToArray();

I would say that it is significantly easier to read. Or add an extension method to convert a span to string directly.

Or you could use Array.Copy

Array.Copy(msg, 0, array1, 0, 4);
Array.Copy(msg, 4, array2, 0, 4);

But I find that less easy to read.

With regards to performance I would not expect a huge difference. I would expect converting the array to a string to take more time than copying a few bytes. But any method that avoid allocations might have some advantage if it is run in a tight loop.

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橙味迷妹 2025-02-12 06:15:14

假设bytelength保持甚至，您可以用以下来用1 替换2个循环：

for (int index = 0; index < halfbytelength; ++index)
{
    Array1[index] = msg[index];
    Array2[index] = msg[index + halfbytelength];
}

注： @JeremyLakeman commented

Assuming that bytelength stays even, you can do the following to replace your 2 loops with 1:

for (int index = 0; index < halfbytelength; ++index)
{
    Array1[index] = msg[index];
    Array2[index] = msg[index + halfbytelength];
}

Note: as @JeremyLakeman commented below, using Array.Copy might be faster.
Your code will also be shorter (1 line per array, with no loops).
(assuming that msg,Array1,Array2 are of array type - which you didn't specify in your question).

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