Netlogo：观察者上下文问题

Question

在为特定补丁运行两个完全相同的过程时，两者中的一个正在说明错误，因为“它不能在观察者上下文中运行，它是一个补丁/乌龟上下文”。

to start
ask patches with [seed = 1 AND age = retirement-age] [retirement]
ask patches with [seed = 1 AND age = death] [successor]
end

退休-age是接口的输入。

死亡是一个补丁属性，我尝试了start过程，以及接口的输入。

使用其他程序中创建的列表，退休和死亡程序只是彼此之间的复制。结果只有不同，请参见下文：

to retirement
;;; other calculations same as successor procedure
 ifelse (successor-result = 1) [set age 35 ] [set over-retirement 1]
end

    to successor
   ;;; other calculations same as retirement procedure
     ifelse (successor-result = 1) [set age 18] [dispatch-parcels] 
    end

运行退休过程不会造成错误，但是后继过程确实会产生错误。

我没有复制所有内容，因为我认为它没有有用因为两个过程完全相同。其他计算使用在观察者上下文中其他过程中创建的全局变量和列表。

此处是dispatch-parcels从一开始就相关补丁程序的过程。

to dispatch-parcels
 ;; this regards the patches with seed = 1 that has been processed in the successor procedure. But doesn't work as for updating the age and death of the agent
  set seed 0
  set age 0
  set death 0

  ;; if there is no successor, the parcels of the farm are distributed along the closest parcels : one farm can distribute its own parcels to multiple different farms
  ask patches with [ ID-farm = [ID-farm] of myself]

  ;; for each parcel, finds the closest parcel and use the ID-farm as the new ID-farm, same for the region in case it changes.
  [
    set ID-farm ([ID-farm] of (min-one-of patches with [(ID-farm != 0) AND (ID-farm != [ID-farm] of myself)]  [distance myself] ))
    set region ([region] of (min-one-of patches with [(region != 0) AND (region != [region] of myself)]  [distance myself] ))
  ]

end

我还尝试使用与退休过程相同的最终命令行进行连续过程，但我收到了相同的错误消息。因此，有关此后继过程的某个地方应该有一些“隐藏”的东西。

关于可能的错误来源的任何洞察力，我应该更加关注什么？

感谢您的时间。

Answer 1

我终于弄清楚了什么问题。很明显，它变得不可见，我有点尴尬。
无论如何，我想分享我的答案，因为它可能会睁开像我这样疲倦的初学者的眼睛。

为了测试我的代码的这一部分，我创建了一个按钮以测试observer上下文中的后继过程，而我编写的命令是不可能的。就是这样。