如何使用Alamofire从Xcode中的API的JSON获取特定对象？

Question

我正在Swift中进行电子商务应用程序的项目，并且必须从我使用mockapi.io创建的API中获得数据，

API的链接为：

[
 {
  "categorie1": "Fruits",
  "categorie2": "Animals",
  "categorie3": "Juices",
  "categorie4": "Vegetables",
  "categorie5": "Alcohol",
  "categorie6": "Desserts",
  "id": "1"
 }
]

/cancorias“ rel =” nofollow noreferrer> https://62858a2ff0e8f0bb7c057f14.mockapi.io/categorias 但是， 响应ws“包含从API获取数据的结构，看起来像这样：

import Foundation

struct ResponseWS:Decodable{
    let Datos:[Categories]
}

struct Categories:Decodable{
    let id: String
    let categorie: String
}

我还有一个名为“ connectws”的文件，我在其中使用Alamofire处理数据：

import Foundation
import Alamofire

class ConnectWS{
    
    static let cmd = ConnectWS()
    private let urlBase = "https://62858a2ff0e8f0bb7c057f14.mockapi.io/categorias"
    private let code = 200...299
    
    func getUsers(user: String, pass: String,success: @escaping(_ user: String) -> (), failure: @escaping(_ error: Error?)-> ()) {
        
        AF.request(urlBase,method: .get).validate(statusCode: code).responseDecodable(of: ResponseWS.self){
            response in
            if let respuesta = response.data {
                
                print(String(decoding: respuesta, as: UTF8.self))
                success(String(decoding: respuesta, as: UTF8.self))
                
            }else{
                
                print(response.error!)
                failure(response.error)
                
            }
        }
    }
}

最后我有了我的ViewController，我想显示数据API：

import UIKit

class ViewControllerCategorias: UIViewController {
    @IBOutlet weak var name: UILabel!
    @IBOutlet weak var message: UILabel!
    @IBOutlet weak var buttonOutlet: UIButton!
    
    
    override func viewDidLoad() {
        super.viewDidLoad()
    }
      
    @IBAction func buttonAction(_ sender: Any) {
        ConnectWS.cmd.getUsers(user: "erik", pass: "1234", success: {user in
            self.name.text = user
        }, failure: {error in
            self.message.text = error.debugDescription
        })
    }
}

它会从API中返回所有数据，而我想做的就是从API中获取特定的“类别”。

如您在“ viewController”中看到的，我有一个按钮，当我单击它时， 按钮，标签显示：

[{"categorie1":"Fruits","categorie2":"Animals","categorie3":"Juices","categorie4":"Vegetables","categorie5":"Alcohol","categorie6":"Desserts","id":"1"}]

如何获得API的特定对象？

Answer 1

您必须将响应数据解码为该对象。您可以使用此通用方法进行解码。只需创建一个模型类/结构，您要在解码JSON后使用该模型/结构。

func decode<T: Codable>(_ data: Data) -> T {
    // Create a decoder
    let decoder = JSONDecoder()
    decoder.keyDecodingStrategy = .convertFromSnakeCase
    
    // Create a property for the decoded data
    guard let results = try? decoder.decode(T.self, from: data) else {
        fatalError("Failed to decode!")
    }
    // Return the ready-to-use data
    return results
}