在React-Navigation V5/V6的屏幕外获取Navigation.State

Question

我正在尝试将一个反应的V4应用程序升级到V5/V6。在v4中，createAppContainer被像这样：

const AppContainer = createAppContainer(AppNavigator);

appnavigator将接收navigation prop，可以使用：

type AppNavigatorProps = {
    navigation: Navigation;
};

class AppNavigator extends Component<AppNavigatorProps> {

    isSplashScreen = (): boolean => {
        const { navigation } = this.props;
        return navigation.state.index === RouteIndexes.SplashScreen;
    };
    render(): ReactNode {
        // styling set-up here

        return (
            <>
                <SafeAreaView style={topStyle} />
                <SafeAreaView style={bottomStyle}>
                    <StatusBar backgroundColor={barColor} />
                    <ErrorBoundary
                        navigation={navigation}>
                        <RootContainerStackNavigator navigation={navigation} />
                    </ErrorBoundary>
                </SafeAreaView>
            </>
        );
    }
}

我无法找到一种方法再在此位置中获取该navigation.state。我有appnavigator navigationContainer而不是createAppContainer so：

<NavigationContainer>
    <AppNavigator />
</NavigationContainer>