我如何计算此变量中有多少个字符，字符串，整数和浮点或双float或double？

Question

String str = "I will give you a 20.5 rupees instead of 20";

我如何计算此变量中有多少个字符，字符串，整数和浮点或双float或double？

像这样的事情：

char chars = 2; // "I" and "a"
String strings = 6; // "will", "give", "you", "rupees","instead" and "of"
int ints = 1; // 20 
double doubles = 1; // 20.5

我想成为这样的输出：

char 2字符串6 int 1 float 1

我练习在上面工作：

int s,f,d,c,i;
String [] splited = str.split("\\s+");
for(int i=0;i<splited.length;i++)
{
    String typee=splited[i].getClass.getName();
    if(typee==string){   
        s=s+1;}
    else if(typee=integer){
        i=i+1;
    }
    else if(typee=float){
        f=f+1;
    }
    else if(typee=char){
        c=c+1;
    }
    else if(typee=double){
        d=d+1;
    }
}
System.out.println("String "+s+"\n int "+i+"\n float "+f+"\n char "+c+"\n double "+d);

Answer 1

 public static void main(String[] args) {
        String str = "I will give you a 20.5 rupees instead of 20";
        String[] array = str.split("\\s", -1);
        int chars = 0;
        int strings = 0;
        int ints = 0;
        int doubles = 0;
        for (int i=0; i<array.length; i++){
            if(array[i].matches("[a-zA-Z]+")){
                if(array[i].length() == 1){
                    chars = chars + 1;
                }
                else{
                    strings = strings + 1;
                }
            }
            if(array[i].matches("[0-9]+")){
                ints = ints + 1;
            }
            if(array[i].matches("[+-]?\\d+\\.?(\\d+)?")){
                doubles = doubles + 1;
            }
        }
        doubles = doubles - ints;
        
        System.out.println("chars: "+ String.valueOf(chars));
        System.out.println("strings: "+  String.valueOf(strings));
        System.out.println("ints: "+ String.valueOf(ints));
        System.out.println("doubles: "+ String.valueOf(doubles));
    }

Answer 2

正如@dangling其他评论中所述，您需要将其转换为各自的数据类型，并且必须维护订单。因为如果您不维护数据类型类型层次结构您将始终获得错误的输出。

这是我的试用，可以有比这更好的方法。

String str = "I will give you a 20.5 rupees instead of 20";
String array[] = str.split("\\s+");
int noofChars=0,noofString=0,noofDouble=0,noOfFloat=0,noofInt =0;
for(String arr : array){

    //Parsing to Integer if succesfull then proced to the next one
    try{
        Integer.parseInt(arr);
        noofInt++;
        continue;
    }catch(Exception e){
        e.getMessage();
    }
    //Parsing to Float if succesfull then proced to the next one
    try{
        Float.parseFloat(arr);
        noOfFloat++;
        continue;
    }catch(Exception e){
        e.getMessage();
    }
    //Parsing to Double if succesfull then proced to the next one
    try{
        Double.parseDouble(arr);
        noofDouble++;
        continue;
    }catch(Exception e){
        e.getMessage();
    }
    // If we are here that means its either character or string .
    // easiest way to check  if length == 1 then its a character
    if(arr.length()==1){
        noofChars++;
        continue;                
    }else{
        noofString++;
    }         
    
    
}

System.out.println("String "+noofString+"\n int "+noofInt+"\n char "+noofChars+"\n double "+noofDouble+"\n float "+noOfFloat);

必须使用try-catch来确保如果无法解析程序，则该程序不应突然结束，然后继续检查下一个数据类型。

Answer 3

public static void main(String[] args) {
    String inputStr = "I will give you a 20.5 rupees instead of 20";
    System.out.println("Decimals:");
    Matcher decimalMatches = Pattern.compile("(\\d+\\.\\d+)").matcher(inputStr);
    while (decimalMatches.find()) {
        System.out.print(Double.parseDouble(decimalMatches.group()) + " ");
    }

    System.out.println();
    System.out.println("Integers:");
    Matcher integerMatches = Pattern.compile("(\\d+)").matcher(inputStr);

    while (integerMatches.find()) {
        System.out.print(Integer.parseInt(integerMatches.group()) + " ");
    }

    System.out.println();
    System.out.println("Characters:");
    Matcher charMatches = Pattern.compile("(^\\w\\s|\\s\\w$|\\s\\w\\s)").matcher(inputStr);
    while (charMatches.find()) { 
        System.out.print(charMatches.group(1) + " ");
    }

    System.out.println();
    System.out.println("Words:");
    Matcher wordMatches = Pattern.compile("(\\w{2,})").matcher(inputStr);

    while (wordMatches.find()) {
        String d = wordMatches.group(1);
        try {
            Integer.valueOf(d);
        } catch (NumberFormatException e) {
            System.out.print(d + " ");
        }
    }
}

输出：

Decimals:
20.5 
Integers:
20 5 20 
Characters:
I   a  
Words:
will give you rupees instead of