在某些情况下，当Callling GREP -C从subprocess.check_output中call tr​​ackback

Question

我对subprocess.check_out的行为非常奇怪：

我想获得grep -c result：

In [50]: !grep -c 'def ' repos/clara.aaa_hotmail.com/*.py
0
In [52]: !grep -c 'def ' repos/saad.aaa_gmail.com/*.py
3
In [53]:

在此方面，我可以很好地得到

In [53]: from subprocess import check_output
In [54]: check_output([f"grep -c 'def ' repos/saad.aaa_gmail.com/*.py"], shell=True)
Out[54]: b'3\n'

：

In [55]: check_output([f"grep -c 'def ' repos/clara.aaa_hotmail.com/*.py"], shell=True)
---------------------------------------------------------------------------
CalledProcessError                        Traceback (most recent call last)
<ipython-input-55-6c66bfb457a5> in <module>
----> 1 check_output([f"grep -c 'def ' repos/clara.aaa_hotmail.com/*.py"], shell=True)

/usr/lib/python3.8/subprocess.py in check_output(timeout, *popenargs, **kwargs)
    413         kwargs['input'] = empty
    414 
--> 415     return run(*popenargs, stdout=PIPE, timeout=timeout, check=True,
    416                **kwargs).stdout
    417 

/usr/lib/python3.8/subprocess.py in run(input, capture_output, timeout, check, *popenargs, **kwargs)
    514         retcode = process.poll()
    515         if check and retcode:
--> 516             raise CalledProcessError(retcode, process.args,
    517                                      output=stdout, stderr=stderr)
    518     return CompletedProcess(process.args, retcode, stdout, stderr)

CalledProcessError: Command '["grep -c 'def ' repos/clara.aaa_hotmail.com/*.py"]' returned non-zero exit status 1.

In [56]:

注意：我们是不处理管道|参见。 python subprocess.check_output GREP组合

Answer 1

您可以用subprocess.check_output用subprocess.run，然后添加captare_output = true

>>> from subprocess import run
>>> run([f"grep -c 'def ' repos/saad.aaa_gmail.com/*.py"],
        shell=True, capture_output=True)
b'3\n'
>>>