如何以增量将当前算法实现为for循环？

Question

我需要循环遵循以下代码的算法。每个循环都应花费第一天（2），并将平均值（.3）添加到其中。

startOrganism = 2
startOrganism = int(input("Starting number of organisms:"))

dailyInc = .3
dailyInc = float(input("Average daily increase (percent): "))

numberDaysMulti = 10
numberDaysMulti = int(input("Number of days to multiply: "))

for x in range(numberDaysMulti):

(Needs to be below)

Day 1  2
Day 2  2.6
Day 3  3.38 
etc.

Answer 1

好的，我假设用户将每天增加百分比为0.3，而不是30：

startOrganism = int(input("Starting number of organisms:"))

dailyInc = float(input("Average daily increase (percent): "))

numberDaysMulti = int(input("Number of days to multiply: "))

percDailyInc = 1 + dailyInc

for day in range(numberDaysMulti):
    print(f'Day {day+1}  {startOrganism:.2f}')
    startOrganism *= percDailyInc

示例输出：

Day 1  2.00
Day 2  2.60
Day 3  3.38
Day 4  4.39
Day 5  5.71
Day 6  7.43
Day 7  9.65
Day 8  12.55
Day 9  16.31
Day 10  21.21

Answer 2

可以使用以下公式来数学处理这种计算：

organisms = starting_organisms * ((1.0 + growth_rate) ^ days)

其中ground_rate是您的情况下的每单位时间增加百分比。然后，简单地打印出每天的价值就成为一个问题。

starting_organisms = int(input("Starting number of organisms:"))
growth_rate = float(input("Average daily increase in percent): "))  #  0.3 = 30%
period = int(input("Number of days to grow:"))

growth = [(starting_organisms * ((1.0 + growth_rate) ** day) for day in range(period)]

# The list 'growth' has all our values, now we just print them out:
for day, population in enumerate(growth):
    print(f"Day {day} {population}")

（这几天使用零索引。也就是说，“第0天”将是您的首发号码。索引以这种方式节省您的错误，但是您可以将打印语句更改为{day {day { + 1}是向用户隐藏此数据结构。）

有一种替代方法，您在每个循环中携带状态，在您迭代时第二天计算。但是，我建议您将计算和显示的关注点分开 - 这种本能将为您提供良好的服务。

grounts = [...对于范围（周期）的一天]是一个列表理解，它的工作方式与单行的前循环。

Answer 3

startOrganism = 0
startOrganism = int(input("Starting number of organisms:"))

dailyInc = 0
dailyInc = float(input("Average daily increase (percent): "))

dayApproximate = 0

numberDaysMulti = 0
numberDaysMulti = int(input("Number of days to multiply: "))

for x in range(numberDaysMulti):

  startOrganism = dailyInc * startOrganism + startOrganism

  print(startOrganism)