如何在特定文本或行上将文本文件拆分为小多个文件？

Question

我有书的txt文件，其中每章中都有单词“ - 末尾”。我想将每个章节分为不同的文件，例如 -

Chapter001.txt
Chapter002.txt
Chapter003.txt
.
.
.
ChapterNNN.txt

我在Python3中写下了以下代码。

groups = open('input.txt').read()
groups_divided = groups.split('-THE END-\n')
temp = group.split('\n')

我现在要它将其分为不同的文件，并给他们命名“章节”。 另外，我没有得到如何拆分和创建文件并确保其涵盖所有查询的方法。

另外，请告诉我是否有任何简单的方法可以通过任何软件进行操作。

Answer 1

您可以通过一次处理输入文本文件来进行操作，而不是通过简单地迭代并累积其中的每一行，直到遇到“结尾”行：

with open('input.txt') as inp:
    n = 1
    chapter = []
    for line in inp:
        if line != '-THE END-\n':
            chapter.append(line)
        else:
            filename = f'Chapter{n:03d}.txt'
            with open(filename, 'w') as outp:
                outp.writelines(chapter)
            n += 1
            chapter = []

Answer 2

另一种方法是查找每个“ - 结尾 - ”的索引，然后使用这些索引创建章节。请参阅以下代码：

with open("my_poem.txt") as f:
    lines = f.readlines()

indices = [0]

for idx, line in enumerate(lines):
    if "-THE END-" in line:
        indices.append(idx) # idx number of line where -THE END- is occurred

chapter_counter = 2

while chapter_counter <= len(indices):
    with open(f"Chapter_{chapter_counter-1}.txt", "a") as w:
        lines_chapter = lines[indices[chapter_counter-2]+1:indices[chapter_counter-1]+1] # From -THE END- to -THE END-
        for line_chapter in lines_chapter:
            w.write(f"{line_chapter}")

    chapter_counter += 1

Answer 3

n = 0
for chapter in groups_divided:
    with open(f'chapter{n}.txt', 'w') as file: 
       file.write(chapter)
       n += 1