我如何df.fillna具有类别中值值
我有一个大的数据集〜1MLN行,约有5000个缺席坐标(我想按“城市”类别填充中位数,但是Fillna正在奏效,如何实现它?
city = ['London', 'Paris', 'Vienna', 'Milan','London', 'Paris', 'Vienna', 'Milan']
lat = [51.510843900000005, 48.8671391, 48.204465500000005, 45.4787357, 51.510843900000005, 48.8671391, None, None]
lng = [-0.1424476, 2.328075, 16.3686397, 9.1961308, -0.14244, 2.329, None, None]
data = pd.DataFrame(list(zip(city, lat, lng)),columns =['city', 'lat', 'lng'])
display(data['lat'].isna().sum()) # 2
display(data['lng'].isna().sum()) # 2
for city_name in set(data['city']):
data[data['city'] == city_name ]['lat'].fillna(data[data['city'] == city_name ]['lat'].median())
data[data['city'] == city_name ]['lng'].fillna(data[data['city'] == city_name ]['lng'].median())
print(city_name, data[data['city'] == city_name ]['lat'].median(),data[data['city'] == city_name ]['lng'].median())
display(data['lat'].isna().sum()) # 2
display(data['lng'].isna().sum()) # 2
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您可以做:
首先 href =“ https://pandas.pydata.org/pandas-docs/stable/reference/reference/pandas.series.fillna.html” rel =“ nofollow noreferrer”> fillna> fillna> fillna 并计算中位数。 (您可以使用任何数学操作)
You could do:
First groupby with the city, then use transform with fillna and calculate the median. (you could use any mathematical operation)