检测音频是否在网站上播放

发布于 2025-02-04 02:05:44 字数 790 浏览 1 评论 0原文

这在某种程度上是这个问题的重复性不了解如何使用接受的答案。此外，这个问题很旧，也许现在有一种更好的方法。

我的用例：

我想测试一般是否与剧作家一起演奏音频。音频源不是DOM元素，因此检查媒体元素不是解决方案。

这就是代码的使用方式：

const isAudioPlaying = page.evaluate(() => {
    /* Code goes here */
})

编辑：这就是媒体播放的代码在其最简单的形式中的样子：

function createAudioPlayer() {
    const audio = new Audio()

    return {
      setSource: (src) => audio.src = src,
      play: () => audio.play,
      pause: () => audio.pause,
      resume: () => audio.resume,
    }
}

该工厂仅将默认的音频构造函数用于播放。它永远不会像那样接触DOM。

原文

This is somewhat a duplicate of this question, but I do not understand on how to use the accepted answer. Furthermore the question is quite old and maybe there is a better way available now.

My use case:

I want to test if audio in general is playing with Playwright. The audio source is not a DOM-Element, so checking media elements is not a solution.

This is how the code would get used:

const isAudioPlaying = page.evaluate(() => {
    /* Code goes here */
})

Edit:
And this is how the code of the media playback looks like in its most simple form:

function createAudioPlayer() {
    const audio = new Audio()

    return {
      setSource: (src) => audio.src = src,
      play: () => audio.play,
      pause: () => audio.pause,
      resume: () => audio.resume,
    }
}

This factory just uses the default Audio constructor for the playback. It never touches the DOM like that.

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