如何使用Django中的ID列表订购相关表

发布于 2025-02-03 23:14:50 字数 1602 浏览 0 评论 0原文

这是我试图执行的示例;

class GroupA(models.Model):
    name=models.CharField(max_length=250)

class GroupB(models.Model):
   category = models.CharField(max_length=250)
   group_a = models.ForeignKey(GroupA)

我有ID列表; [1,2,3]。如何使用ID列表通过groupb执行groupa的顺序。

目前,我要返回的数据的一个示例是;

[
{
"id": 3,
"category": "Category 1",
"group_a": [
   {
     "id": 2,
     "name": "John"
   },
   {
     "id": 1,
     "name": "Doe"
   },
   {
     "id": 3,
     "name": "Jane"
   }
]
}
]

我要存档的是使用ID列表订购group_a的数据; [1,2,3]。因此它将返回这样的东西;

[
{
"id": 3,
"category": "Category 1",
"group_a": [
   {
     "id": 1,
     "name": "Doe"
   },
   {
     "id": 2,
     "name": "John"
   },
   {
     "id": 3,
     "name": "Jane"
   }
]
}
]

//编辑

serializer.py

class GroupASerializer(serializers.ModelSerializer):
    class Meta:
       model = GroupA
       fields = "__all__"
class GroupBSerializer(serializers.ModelSerializer):
    group_a = GroupASerializer(read_only=True, many=True)
    class Meta:
       model = GroupB
       fields = "__all__"

views.pys.py

class GroupBView(APIView):
    serializer_class = GroupBSerializer
    permission_classes = (IsAuthenticated,)

    def get(self, request):
        group_trip = GroupB.objects.all()
        serializer = GroupBSerializer(group_trip, many=True)
        return Response(serializer.data)

here is example of what I am trying to perform;

class GroupA(models.Model):
    name=models.CharField(max_length=250)

class GroupB(models.Model):
   category = models.CharField(max_length=250)
   group_a = models.ForeignKey(GroupA)

I have list of ids; [1, 2, 3]. How do I perform an order of GroupA through GroupB using the list of ids.

Currently, an example of data I am returning is;

[
{
"id": 3,
"category": "Category 1",
"group_a": [
   {
     "id": 2,
     "name": "John"
   },
   {
     "id": 1,
     "name": "Doe"
   },
   {
     "id": 3,
     "name": "Jane"
   }
]
}
]

What I am trying to archive is order the data of group_a using list of ids; [1, 2, 3]. So it would return something like this;

[
{
"id": 3,
"category": "Category 1",
"group_a": [
   {
     "id": 1,
     "name": "Doe"
   },
   {
     "id": 2,
     "name": "John"
   },
   {
     "id": 3,
     "name": "Jane"
   }
]
}
]

//Edit

Serializer.py

class GroupASerializer(serializers.ModelSerializer):
    class Meta:
       model = GroupA
       fields = "__all__"
class GroupBSerializer(serializers.ModelSerializer):
    group_a = GroupASerializer(read_only=True, many=True)
    class Meta:
       model = GroupB
       fields = "__all__"

views.py

class GroupBView(APIView):
    serializer_class = GroupBSerializer
    permission_classes = (IsAuthenticated,)

    def get(self, request):
        group_trip = GroupB.objects.all()
        serializer = GroupBSerializer(group_trip, many=True)
        return Response(serializer.data)

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评论(1

弱骨蛰伏 2025-02-10 23:14:50

也许您应该使用ModelViewSet

class GroupViewSet(viewsets.ModelViewSet):
    queryset = GroupB.objects.all()
    serializer_class = GroupBSerializer
    permission_classes = [permissions.IsAuthenticated]

    def get_queryset(self):
        return GroupB.objects.all().order_by('id')

我没有检查它是否有效

Maybe you should use ModelViewSet

class GroupViewSet(viewsets.ModelViewSet):
    queryset = GroupB.objects.all()
    serializer_class = GroupBSerializer
    permission_classes = [permissions.IsAuthenticated]

    def get_queryset(self):
        return GroupB.objects.all().order_by('id')

I didn't check if it works

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