django测试断言不相等

发布于 2025-02-03 14:29:57 字数 1236 浏览 3 评论 0原文

尝试测试选择器层IM我的应用程序，但是Django不要通过Simle测试。 Queryset看起来很相似，也许我丢了一些东西。

test.py

from django.test import TestCase

from books.models import Author, Book
from books.selectors import get_books


class SelectorTest(TestCase):
    def setUp(self):
        self.author = Author.objects.create(
            name='test_author'
        )
        self.book = Book.objects.create(
            name='test_book',
            category='Drama',
            release_date='2001-01-01',
            author=self.author,
            is_read=True
        )

    def test_get_books(self):
         self.assertEqual(get_books(), Book.objects.all())

selectors.py

from django.db.models.query import QuerySet

from books.models import Book


def get_books() -> QuerySet[Book]:
    """
    Return all objects of Book model.
    """
    books = Book.objects.all()

    return books

断言误差

AssertionError: <QuerySet [<Book: test_book>]> != <QuerySet [<Book: test_book>]>

原文

Trying to test selector layer im my app, but django dont pass simle test. Querysets looks quite similar, maybe i lost something.

test.py

from django.test import TestCase

from books.models import Author, Book
from books.selectors import get_books


class SelectorTest(TestCase):
    def setUp(self):
        self.author = Author.objects.create(
            name='test_author'
        )
        self.book = Book.objects.create(
            name='test_book',
            category='Drama',
            release_date='2001-01-01',
            author=self.author,
            is_read=True
        )

    def test_get_books(self):
         self.assertEqual(get_books(), Book.objects.all())

selectors.py

from django.db.models.query import QuerySet

from books.models import Book


def get_books() -> QuerySet[Book]:
    """
    Return all objects of Book model.
    """
    books = Book.objects.all()

    return books

assertion error

AssertionError: <QuerySet [<Book: test_book>]> != <QuerySet [<Book: test_book>]>

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[旋木] 2025-02-10 14:29:57

您可以使用Django的testcase类中使用transactionTestcase.AsserTactionTestcase.AsserTactionTestcase.AsserTactionTestCase.sertcerysetequal。在此处查看文档。

在您的情况下：

    # …

    def test_get_books(self):
         self.assertQuerysetEqual(get_books(), Book.objects.all())

You can use the TransactionTestCase.assertQuerysetEqual assertion from Django's TestCase class. Check the documentation here.

In your case:

    # …

    def test_get_books(self):
         self.assertQuerysetEqual(get_books(), Book.objects.all())

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绝不放开 2025-02-10 14:29:57

要测试两个QuerySets返回相同的对象，但不一定按相同的顺序返回（当然，假设同一基础模型都在查询相同的基础模型）：

qs1  = Book.objects.all()
qs2 = get_books()
pk1 = qs1.values_list( 'pk', flat=True)
pk2 = q2s.values_list( 'pk', flat=True)

self.assertEqual ( set(pk1), set(pk2) )

这是测试失败时的一条相当有用的消息。您可以获得一个且未确定的PK，而不仅仅是一个不相等的“消息”。

我认为，如果您使用list（）而不是set> set> set（）您请检查两个都以相同的顺序返回相同的对象。

To test that two querysets return the same objects but not necessarily in the same order (assuming both query the same underlying Model, of course):

qs1  = Book.objects.all()
qs2 = get_books()
pk1 = qs1.values_list( 'pk', flat=True)
pk2 = q2s.values_list( 'pk', flat=True)

self.assertEqual ( set(pk1), set(pk2) )

This makes a reasonably useful message when the test fails. You get the pks which are in one and not the other identified, not just a not equal" message.

I think if you use list() instead of set() you get to check that both return the same objects in the same order.

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