无法将新列表数据附加到for循环中的dict

Question

我有一个从ListIP中的帖子返回的IP列表。我想迭代IP的列表并将数据存储在字典中，以便我可以在网页上渲染。但是字典仅覆盖了最后一个IP的值。我该如何解决？目前，ListIP中有3个IP，但DICE仅存储最后一个通过的IPS数据。

def healthcheckresults(request):
if not listip:
    return render(request, "home/homepage.html",)
for ip in range(len(listip)):
    conn = manager.connect(
    host= listip[ip],
    port='22',
    username='XXX',
    password = 'XXX',
    timeout=10
    )
    result = conn.get_ospf_neighbor_information()
    hostnameresult = conn.get_software_information()
    hostname = hostnameresult.xpath('//software-information/host-name/text()')
    ospfneighboraddress = result.xpath('//ospf-neighbor/neighbor-address/text()')
    ospfneighborinterface = result.xpath('//ospf-neighbor/interface-name/text()')
    ospfneighborstate= result.xpath('//ospf-neighbor/ospf-neighbor-state/text()')
    ospfneighborID = result.xpath('//ospf-neighbor/neighbor-id/text()')
    
    ##METHOD1
    ospfdictkey = {"hostname":[],"ospfneighboraddress":[],"ospfneighborinterface":[],"ospfneighborstate":[],"ospfneighborID":[]}
    ospfmetalist = [hostname,ospfneighboraddress,ospfneighborinterface,ospfneighborstate,ospfneighborID]
    for key, value in zip(ospfdictkey, ospfmetalist):
        ospfdictkey[key].append(value)
        
    ##METHOD2
    ospfdict={"hostname":hostname,"ospfneighboraddress":ospfneighboraddress,"ospfneighborinterface":ospfneighborinterface, "ospfneighborstate":ospfneighborstate,"ospfneighborID":ospfneighborID }
    context = {'LUnique': zip(ospfneighboraddress, ospfneighborinterface, ospfneighborstate,ospfneighborID)}
    conn.close_session()

listip.clear()
return render(request, "healthcheck/healthcheckresults.html",{
    "ospfneighboraddress":ospfneighboraddress,
    "ospfneighborinterface":ospfneighborinterface,
    "ospfneighborstate":ospfneighborstate,
    "ospfneighborID":ospfneighborID,
    "context":context,
    "hostname":hostname,
    "listip":listip,
    "ospfdict":ospfdict,
    "ospfdictkey":ospfdictkey,
})

当我检查字典中的数据时，两种提到的方法都返回相同的数据。

{'hostName'：['r3-isp']，'ospfneighboraddress'：['192.168.5.34'，'192.168.5.5'，'192.168.5.10']，'ospfneighborterface'： .0'，'ae3.0']，'ospfneighborstate'：['full'，'full'，full']，'ospfneighborid'：['172.0.0.6'，'172.0.0.0.2'，'172.0.0.0.0.0.0.44 ']}

{'hostName'：[['r3-isp']]，'ospfneighboraddress'：[['192.168.5.34'，'192.168.5.5'，'192.168.5.10'] 'ae10.0'，'ae2.0'，'ae3.0']] '，'172.0.0.2'，'172.0.0.4']]} ['r3-isp']

Answer 1

在每种方法中，您都在覆盖dict。请记住，在每次迭代中，代码都在重复，

for ip in range(len(listip)):

这意味着当您在每种方法的第一行中设置键和值时，您正在覆盖以前使用的任何名称的任何dist。

避免这种情况的一种方法是创建一个空列表，并在创建时附加每个新列表。然后，您可以循环浏览列表以查看每个dict。

aList = []
for ip in range(len(listip)):
...
#Method1
...
aList.append(ospfdictkey )
#Method2
...
aList.append(ospfdict)