在Java中的两个图像视图元素之间旋转时的设定性问题

发布于 2025-02-03 12:35:32 字数 846 浏览 4 评论 0原文

    imageView1.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view)
        {
            if(imageViewGet1.getDrawable() != null){
                imageView1.setVisibility(View.INVISIBLE);
                imageViewGet1.setVisibility(View.VISIBLE);
            }
            OpenGallery1();

        }
    });
    imageView2.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view)
        {
            if(imageViewGet2.getDrawable() != null){
                imageView2.setVisibility(View.INVISIBLE);
                imageViewGet2.setVisibility(View.VISIBLE);
            }
            OpenGallery2();

        }
    });

当我运行代码并打开厨房以选择新照片时，此后，带有旧照片的图像仍然出现如何解决该问题，以便当我选择新映像时，ImageView1消失了，而ImageViewGet则会与新图像一起出现。

原文

    imageView1.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view)
        {
            if(imageViewGet1.getDrawable() != null){
                imageView1.setVisibility(View.INVISIBLE);
                imageViewGet1.setVisibility(View.VISIBLE);
            }
            OpenGallery1();

        }
    });
    imageView2.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view)
        {
            if(imageViewGet2.getDrawable() != null){
                imageView2.setVisibility(View.INVISIBLE);
                imageViewGet2.setVisibility(View.VISIBLE);
            }
            OpenGallery2();

        }
    });

when I run the code and open galley to pick new photo, after that, the imageView with the old one still appear
how I can fix that so when I choose new image, the imageView1 disappear and imageViewGet appear with the new Image.

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月寒剑心 2025-02-10 12:35:32

如果视图重叠，请尝试使用

imageView1.setVisibility(View.GONE);

（一个在第二位）。

.setVisibility(View.INVISIBLE);

只是使视图不可见，但不会隐藏它。

如果这无济于事，则可以使用共享首选项将bool带有image（in）可见性状态。

try to use

imageView1.setVisibility(View.GONE);

if are views overlapping (one is in front of second).

.setVisibility(View.INVISIBLE);

just makes view invisible, but doesn't hide it.

If this won't help, you may can use Shared Preferences to store bool with image (in)visibility state.

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长途伴 2025-02-10 12:35:32

我尝试了一下：

imageView1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view)
            {
                OpenGallery1();

                    imageView1.setVisibility(View.INVISIBLE);
                    imageViewGet1.setVisibility(View.VISIBLE);
                if(imageViewGet1.getDrawable()==null){
                    imageView1.setVisibility(View.VISIBLE);
                }
            }
        });

它可以正常工作。

I tried this :

imageView1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view)
            {
                OpenGallery1();

                    imageView1.setVisibility(View.INVISIBLE);
                    imageViewGet1.setVisibility(View.VISIBLE);
                if(imageViewGet1.getDrawable()==null){
                    imageView1.setVisibility(View.VISIBLE);
                }
            }
        });

and it works fine.

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