REACT Native Hybrid App Notch&#x27的背景彩色更改时

发布于 2025-02-03 11:08:22 字数 200 浏览 2 评论 0原文

很高兴见到你。 我将通过React Native制作一个混合应用程序,即

iPhone Notch区域的颜色,而Android的状态栏则根据特定页面进行更改颜色(例如,如果WebView页面是登录页面,则是Notch的颜色(状态栏)是蓝色 /对于其他页面)紫色),找到WebView的onnavigationStateChange的URL成功,但我想在随后的过程中寻求帮助

Nice to meet you.
I'm going to make a hybrid app by react native

The color of the iPhone's notch area and Android's StatusBar is designed to change colors depending on a specific page (for example, if the webview page is a login page, the color of the notch (StatusBar) is blue / For other pages) purple), finding the url with onNavigationStateChange of webview was successful, but I want to ask for help on what to do in the subsequent process

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梦里梦着梦中梦 2025-02-10 11:08:22

我的方法是这样的,您基本上是根据您刚刚导航到的URL将pagename设置为一些字符串,如果该pagename存在于您的颜色对象中,则状态栏颜色将更改为


//define the colors like:
const statusbarColors = {
    login: "blue",
    default: "green"
}

//in your component set a state (pageName) based on the url you navigate to
 
<SafeAreaView 
    style={{ 
        backgroundColor: statusbarColors[pageName] ?? statusbarColors.default,
        flex: 0 
    }}
/>
<StatusBar 
    backgroundColor={statusbarColors[pageName] ?? statusbarColors.default}
/>
<SafeAreaView style={{flex: 1}}>
    //your screen content
</SafeAreaView>

My approach would be something like this, you basically set pageName to some string based on the url you just navigated to, and if that pageName exists in your colors object then the status bar color will change to it


//define the colors like:
const statusbarColors = {
    login: "blue",
    default: "green"
}

//in your component set a state (pageName) based on the url you navigate to
 
<SafeAreaView 
    style={{ 
        backgroundColor: statusbarColors[pageName] ?? statusbarColors.default,
        flex: 0 
    }}
/>
<StatusBar 
    backgroundColor={statusbarColors[pageName] ?? statusbarColors.default}
/>
<SafeAreaView style={{flex: 1}}>
    //your screen content
</SafeAreaView>
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