我如何使用Plotly Treemap覆盖单个盒子颜色

发布于 2025-02-03 07:28:50 字数 404 浏览 3 评论 0原文

我正在创建一个带有Plitly的Treemap，该treemap按回购中的大小显示文件，并为目录嵌套。我想根据自己的任意规则分配颜色。例如，“以测试_开头的文件是红色的”或“二进制文件为蓝色”。我不使用dataframe，所以我调用treemap（）这样：

fig = px.treemap(names=names, ids=ids, parents=parents, values=values, ...)

我希望通过一个明确具有每个节点的颜色的匹配数组。 treemap（） params color和iNCETE_COLOR_MAP似乎无法正常工作？有没有办法指定每个盒子的颜色？

原文

I'm creating a treemap with Plotly that shows files in a repo by their size, with nesting for the directories. I'd like to assign colors based on my own arbitrary rules. For example "files that start with test_ are red" or "binary files are blue". I'm not using a dataframe so I call treemap() like this:

fig = px.treemap(names=names, ids=ids, parents=parents, values=values, ...)

I was hoping to pass in a matching array that explicitly had the color of every node. The treemap() params color and discrete_color_map don't seem to work that way? Is there a way to specify the color of every box?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

享受孤独 2025-02-10 07:28:50

您可以使用IDS和color进行此操作，然后具有color_discrete_map覆盖每个盒子的颜色。此示例基于我的用例有点奇怪，但它有效：

import plotly.express as px

def create_treemap():
    names = ['a', 'b', 'c', 'd']
    ids = ['a', 'a/b', 'a/c', 'a/c/d']
    parents = ['', 'a', 'a', 'a/c']
    values = [10, 5, 5, 2]

    colors = {
        'a': 'red',
        'a/b': 'green',
        'a/c': 'gold',
        'a/c/d': 'grey'
    }

    fig = px.treemap(names=names, ids=ids, parents=parents, values=values,
                    color=ids,
                    color_discrete_map=colors, 
                    branchvalues='total', title="my treemap")
    fig.update_layout(margin=dict(t=50, l=25, r=25, b=25))
    return fig

create_treemap().show()

它产生：

You can do this with ids and color and then have color_discrete_map override the color of every box. This example is a little weird based on my use case, but it works:

import plotly.express as px

def create_treemap():
    names = ['a', 'b', 'c', 'd']
    ids = ['a', 'a/b', 'a/c', 'a/c/d']
    parents = ['', 'a', 'a', 'a/c']
    values = [10, 5, 5, 2]

    colors = {
        'a': 'red',
        'a/b': 'green',
        'a/c': 'gold',
        'a/c/d': 'grey'
    }

    fig = px.treemap(names=names, ids=ids, parents=parents, values=values,
                    color=ids,
                    color_discrete_map=colors, 
                    branchvalues='total', title="my treemap")
    fig.update_layout(margin=dict(t=50, l=25, r=25, b=25))
    return fig

create_treemap().show()

which produces: