D3.js-检查parenthnode值
我想检查父节点是否等于JSON数据中定义的特定类型。 例如，使用d3.js v4（是的，我知道...），
例如在JSON中：
{"name":"ABC", "type":"3program_outcome_group","children":[{"name":"XY","type":"program_outcome"},...
在此示例中，我想检查父节点的类型（'type'为自定义参数）是否等于3program_outcome_group。同时，我还需要检查子节点是否为program_outcome。
我已经尝试过：
if (d.type == 'program_outcome' && d.parentNode.type == '3program_outcome_group' )
return d.name.substring(0, 6);
但是这是不起作用的...
而在没有检查parenthnode的情况下进行以下工作：
if (d.type == 'program_outcome')
return d.name.substring(0, 4);
我也尝试了：
if (d.type == 'program_outcome' && this.parentNode.type == '3program_outcome_group' )
return d.name.substring(0, 6);
I want to check if a parent node equals a certain type as defined in the JSON data. Using d3.js v4 (yes I know...)
For example in the JSON:
{"name":"ABC", "type":"3program_outcome_group","children":[{"name":"XY","type":"program_outcome"},...
In this example, I want to check if parent node's type ('type' being a custom parameter) is equal to 3program_outcome_group. At the same time, I also need to check if the child node is of type program_outcome.
I have tried:
if (d.type == 'program_outcome' && d.parentNode.type == '3program_outcome_group' )
return d.name.substring(0, 6);
But it's not working...
Whereas the following works without checking the parentNode:
if (d.type == 'program_outcome')
return d.name.substring(0, 4);
I have also tried:
if (d.type == 'program_outcome' && this.parentNode.type == '3program_outcome_group' )
return d.name.substring(0, 6);
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好的，我使用了以下功能来找到自定义“类型”参数的父节点的值：
OK, I used the following which works to find the parent node's value for the custom 'type' parameter: