安排石英作业并在启动中运行

发布于 2025-02-02 18:52:36 字数 712 浏览 4 评论 0原文

我定义了一种调用Web服务的石英工作。我有一个带有cron表达式的触发器，每50分钟以0 0/50 *运行一次？ * * *。我需要在启动应用程序中执行工作，然后每50分钟执行工作。

工作工厂是：

            Trigger trigger = newTrigger().withIdentity(name, "our.trigger")
                                          .withSchedule(CronScheduleBuilder.cronSchedule("0 
                                              0/50 * ? * * *")).startNow().build();
            JobDetail jobDetail = newJob(jobClass).withIdentity(name, "our.job").build();
            Set<Trigger> triggers = new HashSet<>();
            triggers.add(trigger);
            stdScheduler.scheduleJob(jobDetail, triggers, true);
            stdScheduler.start();

如何解决此问题？

原文

I defined a job with Quartz that calls a web service. I have a trigger with Cron expression which run every 50 minutes as 0 0/50 * ? * * * .
I have a requirement that execute the job in startup application and after that every 50 minutes.

the job factory is:

            Trigger trigger = newTrigger().withIdentity(name, "our.trigger")
                                          .withSchedule(CronScheduleBuilder.cronSchedule("0 
                                              0/50 * ? * * *")).startNow().build();
            JobDetail jobDetail = newJob(jobClass).withIdentity(name, "our.job").build();
            Set<Trigger> triggers = new HashSet<>();
            triggers.add(trigger);
            stdScheduler.scheduleJob(jobDetail, triggers, true);
            stdScheduler.start();

How do I solve this issue?

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萌吟 2025-02-09 18:52:36

我通过以下代码解决了问题：

 Trigger startupTrigger = newTrigger().withIdentity(name+".startup", "trigger")
                            .withSchedule(SimpleScheduleBuilder.repeatSecondlyForTotalCount(1)).startNow().build();

感谢@biiyamn

I solved the problem with the following code:

 Trigger startupTrigger = newTrigger().withIdentity(name+".startup", "trigger")
                            .withSchedule(SimpleScheduleBuilder.repeatSecondlyForTotalCount(1)).startNow().build();

Thanks for @biiyamn

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