无法返回无效字段 - typegoose和typegraphql

Question

我有使用TypeGoose和typeGraphQl设置此专辑模型，其中包含来自song使用COMEALSONG Objecttype的多首歌曲：

import {
  prop as Property,
  getModelForClass,
  modelOptions,
  Ref,
} from "@typegoose/typegoose";
import { Field, ObjectType, ID } from "type-graphql";
import { AlbumCategory, } from "./albumCategory.model";
import { Song } from "./song.model";

@ObjectType()
export class AlbumSong {
  @Field(() => ID)
  @Property({ required: true })
  id!: string;

  @Field(() => Song)
  @Property({ type: () => Song, ref: () => Song, required: true })
  song!: Song;
}

@ObjectType({ description: "The Album Model" })
@modelOptions({ schemaOptions: { collection: "albums", timestamps: true } })
export class Album {
  @Field(() => ID)
  id: string;

  @Field()
  @Property({ type: () => String })
  title: string;

  @Field(() => [AlbumSong])
  @Property({ type: AlbumSong })
  albumSongs!: Partial<AlbumSong>[];


  @Field()
  @Property({ required: true, default: Date.now })
  createdAt: Date;

  @Field()
  @Property({ required: true, default: Date.now })
  updatedAt: Date;
}
export const AlbumModel = getModelForClass(Album);

尝试使用

@Query((_returns) => Album, { nullable: false, name: "album" })
async getAlbumById(@Arg("id") id: string) {
  return await AlbumModel.findById({ _id: id });
}

以下方式 查询专辑时GraphQl：

query Album($albumId: String!) {
  album(id: $albumId) {
    id
    albumSongs {
      id
      song {
        id
      }
    }
  }
}

我获取：“无法返回null for nullable field Compulsong.song.song。”

给我看来，参考似乎不起作用，当我仅查询专辑杂志的id 它返回很好...

Answer 1

设置a fieldResolver 在专辑中解决这首歌

@Resolver(() => AlbumSong)
export class AlbumSongFieldResolver {
  @FieldResolver(() => Song)
  async song(@Root() parent: AlbumSong): Promise<Song> {
    return Song.findOne(parent.song);
  }
}