在使用异步时，可以获得期望的控制台输出
function fails4() {
return new Promise((resolve, reject) => {
setTimeout(function () {
reject(new Error());
}, 100);
});
}
async function myFunc4() {
try {
await fails4();
} catch (e) {
console.log(e);
console.log('that failed', e); //<-- this gets called
}
}
async function loadmYScript() {
try {
await myFunc4();
} catch (error) {
console.log(error);
console.log(123);
}
}
loadmYScript();
不能执行控制台。log（123），我期望的任何人都可以帮助我解决这个问题
function fails4() {
return new Promise((resolve, reject) => {
setTimeout(function () {
reject(new Error());
}, 100);
});
}
async function myFunc4() {
try {
await fails4();
} catch (e) {
console.log(e);
console.log('that failed', e); //<-- this gets called
}
}
async function loadmYScript() {
try {
await myFunc4();
} catch (error) {
console.log(error);
console.log(123);
}
}
loadmYScript();
cant't execute the console.log(123) as I expected can anybody help me with this question very appreciated
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您正在调用LoadMyscript，这又调用MyFunc4，而又一次呼叫失败4。最后一个（Fails4）引发了错误。该错误是由MyFunc4“接管”。在此捕获块内部，您不会丢任何错误，只有几个日志，因此LoadMyscript的结果是实现的承诺，并具有不确定的值。它没有被拒绝，因为MyFunc4不会丢失错误。
如果您在MyFunc4的捕获块中丢下错误，则将登录123，承诺将被拒绝。
You're calling loadmYScript, which in turn calls myFunc4, which in turn calls fails4. This last one (fails4) throws an error. The error is "catch-ed" by myFunc4. Inside this catch block you don't throw any error, there's only a couple of logs, so the result of loadmYScript is a fulfilled promise with undefined value. It is not rejected because myFunc4 doesn't throw the error.
If you throw an error inside the catch block of myFunc4, you will have your 123 logged, and the promise will be rejected.