从Xunit中的执行值中获取状态代码

Question

我想比较控制器执行中的返回值，无论是否满足条件。通过调试，我注意到“状态代码”，但没有一种方法来捕获该值进行比较。我的测试代码是

    public void PostAmount_Withdraw_Returns_Null()
    {
        // Arrange
        Amount amount = new Amount() { Id = 0, PaymentDate = DateTime.Today, 
             PaymentTypeId = 3, PaymentAmount = 500, ClientId = 1, Balance = 0 };

        _accountServiceMock.Setup(s => s.Withdraw(amount)).Throws(new Exception());
        
        var target = SetupAmountsController();

        //Act
        var actual = target.PostAmount(amount);

        //Assert

        actual.ShouldNotBeNull();
        //actual.Value.ShouldBe(response);
    }

以下调用控制器方法： -

    public ActionResult<Amount> PostAmount(Amount amount)
    {
        try
        {
            if (amount.PaymentTypeId == 1)
            {
                _accountService.Deposit(amount);
            }
            else if (amount.PaymentTypeId == 2)
            {
                _accountService.Withdraw(amount);
            }
            else
            {
                return Problem("Model 'Amounts'  is null.");
            }
            return new OkObjectResult(new { Message = "Payment Success!" });
        }
        catch (DbUpdateConcurrencyException)
        {
            return Problem("There was error for updating model Payment");
        }
    }

，然后在单位测试执行后返回值

我想在下面提供条件喜欢： -

 actual.Result.StatusCode = HttpStatusCode.BadRequest or 
 actual.Result.StatusCode = 500

Answer 1

刚得到答案。下面将喜欢以下内容： -

 (actual.Result as ObjectResult).StatusCode.ShouldBe((int)HttpStatusCode.InternalServerError);

您需要在此处定义“状态代码”要比较的内容。就我而言，是500。