可以fileInputStream.阅读读取奇数字节吗？

Question

我有一种读取16位波文件的方法：

FileInputStream in = new FileInputStream(file);
byte[] bytes = new byte[8*Number];
do {
    readSize = in.read(bytes, 0, 8*Number);
    ...
} while (...);

然后，我需要将bytes []中的每个字节转换为简短。也就是说，我最好确保readsize偶数！我知道readsize不一定等于8*数字，并且可以更小...

是readsize以某种方式保证的这种奇偶校验通过读取方法，还是我必须在in.Read行之后检查？

edit ，

因为我还需要读取等于8*数字，而不仅仅是我使用此解决方法再一次，直到我得到所有我需要的数据：

        FileInputStream in = new FileInputStream(f);
        int i, readSize, chunkPerBar = 8*Number;
        byte[] bytes = new byte[chunkPerBar];
        double mean;
        do {
            // If I cannot read *exactly* chunkPerBar bytes, keep adding or exit
            readSize = in.read(bytes, 0, chunkPerBar);
            while ((readSize < chunkPerBar) && (in.available() > 0))
                readSize += in.read(bytes, readSize, chunkPerBar - readSize);
            if (readSize < chunkPerBar) break;  // Discard the last chunk if < chunkPerBar

            mean = 0;
            for (i = 0; i < chunkPerBar / 2; i++) {
                aux = (short)( ( bytes[2*i] & 0xff )|( bytes[2*i+1] << 8 ) );
                mean += aux * aux;
            }

            waveform.drawNewBar(mean/chunkPerBar);
        } while (in.available() > 0);
        in.close();
        } catch {...}