当我使用Equatable时，如何发射空状态多次以上

发布于 2025-02-01 03:26:39 字数 446 浏览 4 评论 0原文

我试图发出多次状态，因为我正在验证一种表格，不需要在构造函数上添加任何东西并制作复制功能

。

    class PersonUnValid extends PersonState {

  const PersonUnValid();

  @override
  List<Object> get props => [];

}

  void validate() {
    personKey.currentState!.save();
    if (Formz.validate(personForm.inputs) == FormzStatus.valid) {
      emit(const PersonValid());
      return;
    }
    emit(PersonUnValid());
  }

原文

I am trying to emit a state more than one time because I am validating a form no need to add any thing on the constructor and make copyWith func etc..

so could you help me with other solutions?

    class PersonUnValid extends PersonState {

  const PersonUnValid();

  @override
  List<Object> get props => [];

}

  void validate() {
    personKey.currentState!.save();
    if (Formz.validate(personForm.inputs) == FormzStatus.valid) {
      emit(const PersonValid());
      return;
    }
    emit(PersonUnValid());
  }

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往日 2025-02-08 03:26:39

emit（）如果（状态）相同，则不会发出新状态。这是设计。请参阅：

/// Updates the [state] to the provided [state].
/// [emit] does nothing if the [state] being emitted
/// is equal to the current [state].
void emit(State state) {
...
if (state == _state && _emitted) return;
...

当状态相同时，您期望UI应该更改？

emit() will not emit a new state, if it (the state) is identical. This is by design. See:

/// Updates the [state] to the provided [state].
/// [emit] does nothing if the [state] being emitted
/// is equal to the current [state].
void emit(State state) {
...
if (state == _state && _emitted) return;
...

What do you expect the UI should change when the state is the same?

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