无法在JPA Springboot中找到具有逻辑名称的列

Question

有两个桌子。酒店内的地址。我已经提到了Onetomany的关系。但是编译器投掷错误。

错误创建bean用“ entitymanagerfactory”中定义的name' 路径资源 [org/springframework/boot/autoconfigure/orm/jpa/hibernatejpaconfiguration.class]： init方法的调用失败；嵌套异常是 org.hibernate.mappingException：无法找到具有逻辑的列 名称：org.hibernate.mapping.table（地址）及其 相关的超级物品和辅助表

饭店。java

@AllArgsConstructor
@Data
@Entity
@Table(name = "hotels")
@NoArgsConstructor
public class HotelEntity {

    @Id @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "hote_id")
    private String hotelId;
    @Column(name = "hotel_name")
    private String hotelName;
    @Column(name = "build_date")
    private Date buildDate;
    @Column(name = "guest_type") @Enumerated(EnumType.STRING)
    private GuestType guestType;
    @Column(name = "room")
    @OneToMany(targetEntity = RoomEntity.class,cascade = CascadeType.ALL)
    @JoinColumn(name = "hotel_room", referencedColumnName = "roomId")
    private List<Room> room;
    @OneToOne(targetEntity = AddressEntity.class,cascade = CascadeType.ALL)
    @JoinColumn(name = "hotel_address", referencedColumnName = "addressId")
    private Address hotelAddress;

地址。java

@Entity
@Table(name = "ADDRESS")
@Getter
@Setter
@ToString
@RequiredArgsConstructor
public class AddressEntity {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "address_id")
    private String addressId;
    @Column(name = "street_name")
    private String streetName;
    @Column(name = "city")
    private String city;
    @Column(name = "zip_code")
    private String zipCode;
    @Column(name = "country")
    private String country;
}

我尝试了一些更改的变量名称，如果我缺少某些东西，也要仔细检查。但是看起来我遵循的方式与其他堆栈溢出问题中提到的方式相同。我想念什么吗？

Answer 1

引用的columnname应参考@column名称，而不是Java属性名称
Change readecce> readeccecolumnName从selidse> selidseid值 to address_id

 @JoinColumn(name = "hotel_address", referencedColumnName = "address_id")
        private Address hotelAddress;