嵌套的匿名函数不会运行（JavaScript）

发布于 2025-01-31 12:55:22 字数 453 浏览 4 评论 0原文

我正在尝试制作一个嵌套匿名函数的回调函数。我的代码看起来像这样：

    function submitGuess(guess) {
        if (guess.length === 5) {
            console.log("The guess was 5 letters");
            const postGuess = async () => {
                console.log("Anon function initiated")
                const res = await fetch(SOME_URL);
            }
        }
    }
    submitGuess(guess)

但是匿名函数从未启动。第二个console.log永远不会运行，我不知道为什么。

原文

I am trying to make a callback function that has an anonymous function nested inside. My code looks something like this:

    function submitGuess(guess) {
        if (guess.length === 5) {
            console.log("The guess was 5 letters");
            const postGuess = async () => {
                console.log("Anon function initiated")
                const res = await fetch(SOME_URL);
            }
        }
    }
    submitGuess(guess)

But the anonymous function never initiates. The second console.log never runs, and I can't figure out why.

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寄人书 2025-02-07 12:55:22

新答案：感谢您的反馈

// declare the function
async function submitGuess(guess) {
    if (guess.length === 5) {
        console.log("The guess was 5 letters");
        const postGuess = async () => {
            console.log("Anon function initiated")
            const res = await fetch("url");
        };
        await postGuess(); // call the function
    }
}

submitGuess("input");

旧：
确保您声明功能，然后打电话给它们！

// declare the function
function submitGuess(guess) {
    if (guess.length === 5) {
        console.log("The guess was 5 letters");
        postGuess(); // call the function
    }
}

// declare the function
const postGuess = async () => {
    console.log("Anon function initiated")
    const res = await fetch(SOME_URL);
}

submitGuess(guess)

NEW ANSWER: THANKS FOR FEEDBACK

// declare the function
async function submitGuess(guess) {
    if (guess.length === 5) {
        console.log("The guess was 5 letters");
        const postGuess = async () => {
            console.log("Anon function initiated")
            const res = await fetch("url");
        };
        await postGuess(); // call the function
    }
}

submitGuess("input");

OLD:
Make sure you declare the functions then you call them !!

// declare the function
function submitGuess(guess) {
    if (guess.length === 5) {
        console.log("The guess was 5 letters");
        postGuess(); // call the function
    }
}

// declare the function
const postGuess = async () => {
    console.log("Anon function initiated")
    const res = await fetch(SOME_URL);
}

submitGuess(guess)

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