如果有重复
我不知道是否有解决这个问题的方法,但这是我想做的 我有这个数组,
array=[
{'id': 1, 'isActive': true, 'name': apple},
{'id': 2, 'isActive': false, 'name': orange},
{'id': 3, 'isActive': false, 'name': apple},
{'id': 4, 'isActive': false, 'name': apple},
{'id': 5, 'isActive': false, 'name': orange},
{'id': 6, 'isActive': false, 'name': forest}
{'id': 7, 'isActive': false, 'name': forest}
]
我想在此数组中绘制绘制,但我只想在没有重复的情况下显示数组,但没有更改数组!我正在考虑添加另一个价值,所以
array=[
{'id': 1, 'isActive': true, 'name': apple, 'isShown': true},
{'id': 2, 'isActive': false, 'name': orange, 'isShown': true},
{'id': 3, 'isActive': false, 'name': apple, 'isShown': false},
{'id': 4, 'isActive': false, 'name': apple, 'isShown': false},
{'id': 5, 'isActive': false, 'name': orange, 'isShown': false},
{'id': 6, 'isActive': false, 'name': forest, 'isShown': true},
{'id': 7, 'isActive': false, 'name': forest, 'isShown': false},
]
我想这样的是这样,但我不知道该怎么做:x任何帮助或提示?
i don't know if there's a solution to this problem but here's what i want to do,
i have this array
array=[
{'id': 1, 'isActive': true, 'name': apple},
{'id': 2, 'isActive': false, 'name': orange},
{'id': 3, 'isActive': false, 'name': apple},
{'id': 4, 'isActive': false, 'name': apple},
{'id': 5, 'isActive': false, 'name': orange},
{'id': 6, 'isActive': false, 'name': forest}
{'id': 7, 'isActive': false, 'name': forest}
]
i want to map through this array but i only want to show the array without duplicates but without changing the array ! i was thinking about adding another value so it will be like this
array=[
{'id': 1, 'isActive': true, 'name': apple, 'isShown': true},
{'id': 2, 'isActive': false, 'name': orange, 'isShown': true},
{'id': 3, 'isActive': false, 'name': apple, 'isShown': false},
{'id': 4, 'isActive': false, 'name': apple, 'isShown': false},
{'id': 5, 'isActive': false, 'name': orange, 'isShown': false},
{'id': 6, 'isActive': false, 'name': forest, 'isShown': true},
{'id': 7, 'isActive': false, 'name': forest, 'isShown': false},
]
I thought about this but i didn't know how to do it :x Any help or tips ?
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