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如何从Python的URL获取标题和简要说明？

发布于 2025-01-31 09:57:56 字数 232 浏览 2 评论 0原文

在不和谐中，如果发布链接，Discord将找到标题，并简要摘要：

我如何在Python中复制此行为？

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无语# 2025-02-07 09:57:56

与此类似： https://stackoverflow.com/a/a/43154489/99964778

您需要获得一些价值元标记以“ OG”开头。在您的示例标题，描述，图像等元数据以及其他字段

<meta property="og:site_name" content="livescience.com">
<meta property="og:image" content="https://cdn.mos.cms.futurecdn.net/W3wpBCQ4hEL4dthLYnsosK-1200-80.gif">
<meta property="og:image:width" content="1200">
<meta property="og:type" content="article">
<meta property="article:publisher" content="https://www.facebook.com/livescience?cmpid=556687">
<meta property="og:title" content="Alien shopping-bag ocean weirdo has glowing Cheetos for guts">
<meta property="og:url" content="https://www.livescience.com/alien-glowing-cheeto-sea-cucumber">
<meta property="og:description" content="The deep-sea creature surprised scientists.">

Similar to this SO: https://stackoverflow.com/a/43154489/9964778

You need to get the value of some meta tags which starts with "og". In your example, you have in the source code below with the related metadata for title, description, image, among other fields

<meta property="og:site_name" content="livescience.com">
<meta property="og:image" content="https://cdn.mos.cms.futurecdn.net/W3wpBCQ4hEL4dthLYnsosK-1200-80.gif">
<meta property="og:image:width" content="1200">
<meta property="og:type" content="article">
<meta property="article:publisher" content="https://www.facebook.com/livescience?cmpid=556687">
<meta property="og:title" content="Alien shopping-bag ocean weirdo has glowing Cheetos for guts">
<meta property="og:url" content="https://www.livescience.com/alien-glowing-cheeto-sea-cucumber">
<meta property="og:description" content="The deep-sea creature surprised scientists.">

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