我可以使用JS fetch（）API从Formspark获取表单数据吗？

发布于 2025-01-31 09:50:25 字数 878 浏览 0 评论 0 原文

当我从 formspark文档我们可以使用 get get formspark中的方法。如果我正确理解，则 get 方法在JS fetch（）API中表示我们要从某个地方检索数据。因此，我编写了此代码以获取使用JS Fetch方法的数据（从Formspark中提交的数据之前创建的数据：

async function fetchText() {
    let response = await fetch('https://submit-form.com/my-id', {
        method: "GET",
        headers: {
            "Content-Type": "application/json",
            Accept: "application/json",
        }
    })
    let data = await response.json();
    console.log(data);
    return data;
}

fetchText().then(r => console.log(r));

但这给了我一个空的对象作为响应数据！虽然我的帐户中有六个提交的内容。有人可以帮我，我的代码中的错误吗？

原文

As I read from formspark documentation we can use GET methods in formspark. If I understood correctly, the GET method in JS fetch() API means that we want to retrieve data from somewhere. So I wrote this code to get my data (data that were created before from submissions in formspark) with JS fetch method:

async function fetchText() {
    let response = await fetch('https://submit-form.com/my-id', {
        method: "GET",
        headers: {
            "Content-Type": "application/json",
            Accept: "application/json",
        }
    })
    let data = await response.json();
    console.log(data);
    return data;
}

fetchText().then(r => console.log(r));

But it gives me an empty object as a response data! while I have six submissions in my account now. Could someone please help me that what is wrong in my code?

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东京女 2025-02-07 09:50:25

后端返回以下消息此表单不再存在。

如果我对文档中的URL样本进行相同的操作。它给我以下错误

因此，您需要做什么是用URL中的表单ID替换 my-id （例如 https：// submit-form.com/22 ）。

这是应用更改的片段

async function fetchText(formId) {
    let response = await fetch(`https://submit-form.com/${formId}`, {
        method: "GET",
        headers: {
            "Content-Type": "application/json",
            Accept: "application/json",
        }
    })
    let data = await response.json();
    console.log(data);
    return data;
}

const targetFormId = 441; // Here should be a valid actual form ID

fetchText(targetFormId).then(r => console.log(r));

The backend returns the following message This form does not exist anymore.

If I do the same with the URL sample from the documentation. It gives me the following error

So what do you need to do is to replace the my-id with your form ID in the URL (e.g https://submit-form.com/22).

Here is the snippet with the change applied

async function fetchText(formId) {
    let response = await fetch(`https://submit-form.com/${formId}`, {
        method: "GET",
        headers: {
            "Content-Type": "application/json",
            Accept: "application/json",
        }
    })
    let data = await response.json();
    console.log(data);
    return data;
}

const targetFormId = 441; // Here should be a valid actual form ID

fetchText(targetFormId).then(r => console.log(r));

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